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9966 [12]
3 years ago
8

............……Ayuda porfis

Mathematics
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

Ok

Step-by-step explanation:

V125BC [204]3 years ago
7 0

Answer:

-11

Step-by-step explanation:

that's it's the answer

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How to find the y-intercept from a table AND from a graph.
ExtremeBDS [4]

Answer:

When Finding the Y-Intercept from a Graph and Table, you are searching for the point of intersection between the equation and the y-axis. When finding the Y-Intercept from a Graph, you should find where the line from the equation crosses the y-axis. The point where the equation crosses the y-axis is the Y-Intercept.

Step-by-step explanation:

6 0
3 years ago
Show that √(1-cos A/1+cos A) =cosec A - cot A​
Gennadij [26K]

Hi there!

\sqrt{\frac{1-cosA}{1+cosA}} =

We can begin by multiplying by its conjugate:

\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}}  = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =

Simplify using the identity:

1 - cos^2A = sin^2A

\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =

Take the square root of the expression:

{\frac{sinA}{1+cosA} =

Multiply again by the conjugate to get a SINGLE term in the denominator:

{\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\

Simplify:

{\frac{sinA(1-cosA)}{1-cos^2A} =

Use the above trig identity one more:

{\frac{sinA(1-cosA)}{sin^2A} =

Cancel out sinA:

{\frac{(1-cosA)}{sinA}  =

Split the fraction into two:

{\frac{1}{sinA}   - \frac{cosA}{sinA} =

Recall:

1/sinA = cscA\\\\cosA/sinA = cotA

Simplify:

\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}

5 0
2 years ago
Solve the equation for all real solutions in simplest form.<br> 3x2 - 12x + 11 = x
Ivanshal [37]

Answer:

(13 + or - (sign) square root(37)) / 6

Step-by-step explanation:

First search up the quadratic formula which is

x = (- b + or - square root(b^2 - 4ac)) / 2a

and to find a, b, and c you need this formula

ax^2 + bx + c = 0 (btw this is the safest solution to finding your answer with a number in-front of a quadratic equation.)

Math:

a = 3, b = -13, c = 11

b = -13, because of the x on the other end of the equation as the equation above "ax^2 + bx + c = 0" you need the zero to proceed to this next step.

Side Note: You only take the number and not the variable, variables are x, y, w, z, or etc.

(- (- 13) + or - square root((-13)^2 - 4(3)(11) ) ) / 2 * 3

13 + or - square root(37) / 6

5 0
2 years ago
josh has a job mowing lawns. He charges$25 for each yard. He needs at least $400 for the new game system that he wants. write an
Murljashka [212]

25x\geq400

x\geq16

Hope Your Thanksgiving Went Well, Here's Some Help Cleaning Up

-TheKoolKid1O1

5 0
4 years ago
Which equation best matches the graph shown below?
n200080 [17]

Answer:

y= 0.2(x+1)^2+5 (Bottom left answer)

Step-by-step explanation:

Hope this helps :)

6 0
2 years ago
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