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mrs_skeptik [129]
3 years ago
12

Jack is going to an amusement park. The price of admission into the park is $40, and once he is inside the park, he will have to

pay $5 for every ride he rides on. How much money would Jack have to pay in total if he goes on 14 rides? How much would he have to pay if he goes on rr rides? cost for 14 rides: cost for r rides:
Mathematics
1 answer:
sashaice [31]3 years ago
5 0

Step-by-step explanation:

for 14 rides its 70 so you already don't have enough

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Answer:

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Step-by-step explanation:

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2 years ago
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An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
seraphim [82]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean compression strength from the extra carbonation of strawberry drink and μ2 be the mean compression strength from the extra carbonation of cola.

The random variable is μ1 - μ2 = difference in the mean compression strength from the extra carbonation of strawberry drink and the mean compression strength from the extra carbonation of cola.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

This is a left tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 530

x2 = 553

s1 = 23

s2 = 16

n1 = 10

n2 = 10

t = (530 - 533)/√(23²/10 + 16²/10)

t = - 2.6

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [23²/10 + 16²/10]²/[(1/10 - 1)(23²/10)² + (1/10 - 1)(16²/10)²] = 6162.25/383.752

df = 16

We would determine the probability value from the t test calculator. It becomes

p value = 0.0097

Since alpha, 0.05 > than the p value, 0.0097, then we would reject the null hypothesis. Therefore, at 5% significance level, the data suggests that the extra carbonation of cola results in a higher average compression strength.

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3 years ago
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This is how you would solve the question.
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First find the amount of each payment:
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