757 units squared. Here is work:
20 in. Because if you divide it by three then multiply it by four you get your answer.
Answer:
The air is .6m^3
Step-by-step explanation:
The volume of a cube is
V = s^3 where s is the side length
The volume of the tank is
V = 1^3 = 1 m^3
The volume of the water is 1 by 1 by .4
V = l*w*h
= 1 *1*.4
= .4 m^3
The difference must be filled by air
1- .4 = .6 m^3
The air is .6m^3
Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
