Answer:
Bl^2+4Bl*Fh
Step-by-step explanation:
I'm not quite certain what "draw a net" means here. But for part b, we are doing the formula. The bottom part is a square(assumingly so take this with a grain of salt), thus making the base equal to 3*3 cm or 9 cm^2. The triangular faces are each 3*2.24 cm or 6.72 cm^2. We then multiply this by 4 to get 26.88. Thus, the equation is Bl^2(Base length squared)+Bl*Fh(Face height, I forgot the official name sorry about that)*4 for part b.
What we know is that a 6 foot tall tent casts a 15 foot shadow. Lets represent that given this way: 6 = 15
So, the unknown (y), or what we want to know, is how tall the cardboard box if it has a 6 foot long shadow (noticeably the same height as the tent):
y = 6
6 = 15
y = 6
(6 x 6) / 15 = y
36 / 15 = y
2.4 = y
The height of the cardboard box is 2.4 feet.
Answer:
55 degrees
Step-by-step explanation:
All angles in a triangle must equal 180 degrees when added together
They provide you with 2 angles 35 degrees and 90 degrees
So, you add 35 + 90 = 125
So you know that the 2 angles they give you equal 125 degrees
Now, you subtract 180 - 125 = 55
So the missing angle is 55 degrees
Answer:
We know length of one quarter of a circle = 2πr/4 = πr/2
So here we can make the equation for to find thr value of radius r
length of one quarter given = 25 cm
so πr/2 = 25 cm
=> πr = 50 cm
=> r = 50/π cm
So the entire circumference of circle =
2πr
= 2 π 50/π cm
= 100π/π cm (ans)
Here we dont substitute the value of π due to represent the answer in terms of pi.
Hope it helps you
