<h3>Answer: The lines are perpendicular</h3>
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Work Shown:
Use the slope formula to find the slope of the line through the two given points.
m = (y2 - y1)/(x2 - x1)
m = (-4 - (-5))/(6 - (-7))
m = (-4 + 5)/(6 + 7)
m = 1/13
The slope of the line through the two given points is 1/13.
This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.
However, the two lines are perpendicular because multiplying the two slope values leads to -1
(slope1)*(slope2) = (-13)*(1/13) = -1
note: It might help to think of -13 as -13/1 to help multiply the fractions.
Answer:
0.54kilometres
Step-by-step explanation:
a)actual distance =2.7*20000
=54000cm
=0.54kilometres
2x^2 + 5x + 2 = 0
(x + 2)(2x + 1) = 0
x = -2 x = - 1/2
Letter C
Answer:
13 square units
Step-by-step explanation:
The bounding rectangle is 4 units wide and 5 units high, so has an area of 4×5 = 20 square units. From that are subtracted the areas of 4 triangles. 2 of them are 3 wide and 1 high, so have a combined area of 3×1 = 3 square units. The other two are 1 wide and 4 high, so have a combined area of 1×4 = 4 square units.
Then the area of the parallelogram is ...
20 -3 -4 = 13 . . . . square units
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)