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Gemiola [76]
3 years ago
6

What is the greatest common factor of 4k, 18k4, and 12? 2 4 2k 4k

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

Greatest Common Factor is 2

Step-by-step explanation:

Greatest Common Factor is the highest factor that will divide all the numbers. To find the Greatest common factor, first we need to find out the numbers that all the values have in common.

Factors of 4k=1, 2, 4 and k

Factors of 18k=1, 2 , 3, 6, 9, 18 and k

Factors of 12=1, 2, 3, 4, 6 and 12

Common factors are = 1 and 2.

Therefore,

Greatest Common Factor = 1\times2

                                           =2

nikitadnepr [17]3 years ago
4 0

Answer:

Its A. 2

Just took it.

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The cost of C (in dollars) of making n watches is represented by C=15n+85. How many watches are made when the cost is $385?
hichkok12 [17]

well...

15 x 20 = 300

300+85 = 385


you can get 20 watches for $385


4 0
3 years ago
Solve for the compound inequality 6b < 42 or 4b + 12 > 8.
Anuta_ua [19.1K]

Answer:

-1<b<7, or i suppose b.

Step-by-step explanation:

6b<42

b<7

4b+12>8

4b>-4

b>-1

6 0
3 years ago
Someone plz help me with this??????????!!!!!!!!!!
attashe74 [19]

Answer:

The answer is B.

Step-by-step explanation:

3 times 3 is 9. 2 times -6 is -12. 9 + -12 is -3.

9 times 3 is 27. 4 times -6 is -24. 27 + -24 is 3.

8 0
3 years ago
Given the figure below solve for X
enot [183]

Answer:

x = 37

Step-by-step explanation:

7 0
2 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete sidewalk surrounds the pool and is a constant 2 fee
Naddika [18.5K]

Answer:

The dimensions of the pool are:

Width: 8.944 feet

Length: 17.888 feet

Step-by-step explanation:

From Geometry, the area of a rectangle (A), measured in square feet, is determined by the following equations:

A = w\cdot l (1)

Where:

w - Width, measured in feet.

l - Length, measured in feet.

If we know that w = x, l = 2\cdot x and A = 160\,ft^{2}, then we get the following second order polynomial:

2\cdot x^{2}-160 = 0 (1)

And we solve the expression for x:

2\cdot x^{2} = 160

x^{2} = 80

x = \sqrt{80}\,ft

x \approx 8.944\,ft

Then, the dimensions of the pool are, respectively:

w \approx 8.944\,ft and l \approx 17.888\,ft

5 0
3 years ago
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