The proportion would look like:-
118 59
------- = --------
13 z
Solve for z:-
13 × 59 = 767
767 ÷ 118 = 6.50
so z = 6.50
Check your work
118 × 6.50 = 767
13 × 59 = 767
So, z = 6.50
Hope i helped ya!!
Answer:
Below:
Step-by-step explanation:
A) 0.15 (0.35 + 0.40 + 0.10 + 0.15 = 1)
B) 0.45
C) 0.40
Answer:
1 5/6
Step-by-step explanation:
2x + y = -1
y = -2x - 1....the slope here is -2.
A parallel line will have the same slope.
y = mx + b
slope(m) = -2
(0,-2)....x = 0 and y = -2
now we sub and solve for b, the y int
-2 = -2(0) + b
-2 = b
so ur parallel equation is : y = -2x - 2 <==
=================
so our original equation has a slope of -2
A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we " flip " the slope and change the sign....-2 (or -2/1).....flip the slope and it becomes -1/2.....change the sign...and it becomes 1/2. So our perpendicular line will have a slope of 1/2.
y = mx + b
slope(m) = 1/2
(0,-2)...x = 0 and y = -2
now we sub and find b, the y int
-2 = 1/2(0) + b
-2 = b
so ur perpendicular equation is y = 1/2x - 2 <==
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>