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Galina-37 [17]
3 years ago
7

Segment Y prime Z prime has endpoints located at Y'(0, 3) and Z'(−6, 3). segment YZ was dilated at a scale factor of 3 from the

origin. Which statement describes the pre-image?
A. segment YZ is located at Y (0, 9) and Z (−18, 9) and is three times the size of segment Y prime Z prime.
B. segment YZ is located at Y (0, 3) and Z (−6, 3) and is the same size as segment Y prime Z prime.
C. segment YZ is located at Y (0, 1.5) and Z (−3, 1.5) and is the one-half the size of segment Y prime Z prime.
D. segment YZ is located at Y (0, 1) and Z (−2, 1) and is one-third the size of segment Y prime Z prime.

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

D. Segment YZ is located at Y(0,1) and Z(−2,1) and is one-third the size of segment Y'Z'

Step-by-step explanation:

When you dilate a point by a factor of x from the origin, you multiply its coordinates by the same factor.

Thus, if the coordinates of the original point are (1,2) and the scale factor is 3, those of its image are (3,6).

If Y'Z' has endpoints at Y'(0,3) and Z'(-6,3) and was dilated by a factor of 3, the coordinates of the endpoints of the pre-image were ⅓ those of the image.

The figure below shows the segments YZ and Y'Z'.

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MEC makes a big family tent in the shape of a symmetrical triangular prism. The floor of the tent is 5 m long and 2.5 m wide. Th
SVEN [57.7K]

Answer:

15,236 sq in

Step-by-step explanation:

First, you have to split the net into three rectangles and two triangles

step 1

triangular base area

1/2 bh = 1/2 (44 in)(64 in)

= 1/2 (2,816 sq in)

= 1,408 sq in.

2 x 1,408 sq in = 2,816 sq in.

step 2

end rectangle area

lw = (68 in)(69 in)

= 4,692 sq in

2 x 4,692 sq in = 9,384 sq in

Now find the area of the middle rectangle

lw - (69 in) (44 in) = 3,039 sq in.

then add all the areas together

2,816 + 9,384 + 3,036 = 15,236 sq in

Hope this helps :)

3 0
3 years ago
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2BD = 12\sqrt{3} ( divide both sides by 2 )

BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

4 0
3 years ago
Pythagorean Theorem: Jason only has room for a TV that is less than 30” wide.
Tasya [4]

Answer:

No

Step-by-step explanation:

Using the Pythagorean Theorem, make 40 = c, 24 = b and the remaining side (the width) = a.

Solving for a we get a = \sqrt{c^2-b^2}. Then plugging in the values for c and b, we get a = \sqrt{1024} = 32

Since the width of the TV needs to be less than 30" wide, it will not fit since the width of the TV is 32" wide.

5 0
3 years ago
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2/5 + p = 4/5 + 3/5p
nexus9112 [7]

Answer:

1

Step-by-step explanation:

6 0
3 years ago
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2x+3y=41 and 5x+4y=85
Sever21 [200]

Answer:

5x+4y=85-

 Slope = -2.500/2.000 = -1.250

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 y-intercept = 41/3 = 13.66667

5 0
3 years ago
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