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AysviL [449]
3 years ago
6

Why does a calculator return an error when trying to find inverse sine of 1.055?

Mathematics
2 answers:
anyanavicka [17]3 years ago
6 0
Sin(x) is a function bounded between -1 and 1. A value greater than 1 or smaller than -1 (-1.1, for instance) does not correspond to any real angle.

It then returns error

Len [333]3 years ago
6 0

Answer:

1.055 is outside the domain of the sine function.


Step-by-step explanation:

<em>When we are taking the inverse sine, we are finding an angle that gives a value of 1.055. </em>

The sine function NEVER gives a value greater than 1 or less than -1. The domain of the sine function is between -1 and 1, inclusive.

So wanting to know which angle gives a sine value of 1.055 is futile. Sine can never be greater than 1.

That's why the calculator gives an error, because 1.055 is outside the domain of the sine function.

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Hope I helped!
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Let Z = 5 + 12i, The value of |Z| is
gtnhenbr [62]

Answer: 13

Step-by-step explanation:

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3 0
3 years ago
Find the formula for the nth term in this arithmetic sequence a1=0 a2=.5 a3=1 a4=1.5
UkoKoshka [18]

Answer:

Step-by-step explanation:

The arithmetic sequence usually write as a_{n}=a_{1}  +(n-1)d, where a1 is the first term and d is a common difference.

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7 0
3 years ago
Suppose a 95% confidence interval for μ turns out to be (1,000, 2,100). To make more useful inferences from the data, it is desi
Nat2105 [25]

Answer:

a) Increase the sample size

Step-by-step explanation:

Given that a 95%  confidence interval for μ turns out to be (1,000, 2,100)

The confidence interval is formed as

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Margin of error = critical value * std dev/sqrt of sample size

Hence for the same confidence level, we cannot change critical value.

The only available ways are either to decrease std deviation or increase the sample size to make it narrower.

If confidence level becomes higher, then confidence interval would be wider.

Here  out of four options the correct option is

a) Increase the sample size

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