For each inequality, find two For each inequality, find TWO values for that make the inequality true.

Mathematics

1 answer:

Sergio [31]3 years ago

3 0

Answer: Choice D and Choice E

Explanation:

Subtract 3 from both sides

x+3 > 70

x+3-3 > 70-3

x+0 > 67

x > 67

Any number larger than 67 will make the original inequality to be true.

Unfortunately, only E) 70 fits the description.

D) 67 won't work since 67 > 67 is false.

However, I have a feeling that the original inequality might be $x+3 \ge 70$ . If so, then 67 would work because $67\ge 67$ is true.

So I'll assume that this is the inequality you meant to type out.

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babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

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For question 10, it states $\frac{1}{4}$ . This can be split into $\frac{3}{x}$ and $\frac{3}{x}$ . When x is 12 in the first equation then $\frac{3}{12} = \frac{1}{4}$ and when x is 6 in the second equation $\frac{3}{6} =0.5$ (0.5 is also $\frac{1}{2}$ ). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.