Answer:
(1) 102.55 in
(2) 316.69 in²
Step-by-step explanation:
Applying (1)
a² = b²+c².............. Equation 1
Given: a = 25 in, b = 20 in,
25² = 20²+b²
b² = 25²-20²
b² = 225
b = √225
b = 15 in
b = diameter of the semicircle
The lenght of the semicircle = πd/2 = 3.14×15/2 = 23.55 in
Therefore,
P = 37+25+17+23.55 = 102.55 in
(2) Applying,
A = Area of the tripezium- area of the semi circle
A = [h(a+b)/2]-πh²/8.............. Equation 2
Given; h = 15 in, a = 17 in, b = 37 in
A = (15(17+37)/2)-(3.14×15²/8)
A = 405-88.31
A = 316.69 in²
I hope this helps you
A=Area
b=base
h=height
A=b×h/2
A=1/2.b+1/2.h
The relation you have shown is not a function.
In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.
One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.
Step-by-step explanation:

value of x is 7
hope this answer helps you dear....take care!
Answer:
9
Step-by-step explanation:
H=1/2 * B
N=H-5= 1/2 * B-5
B+H+N= B+(1/2 *B) + (1/2 *B-5)=31
2B-5=31
B=18
H=1/2 *B=9