Answer:
The average rate of change of rainfall in the rainforest between 2nd year and 6th year = <u>3 inches</u>
Step-by-step explanation:
Given function representing inches of rainfall:
To find the average rate of change between the 2nd year and the 6th year.
Solution:
The average rate of change between interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
is given as :
For the given function we need to find the average rate of change between 2nd year and 6th year. ![[2,6]](https://tex.z-dn.net/?f=%5B2%2C6%5D)
So, we have:
Thus, average rate of change will be:
⇒ 
⇒ 
⇒ 
Thus, the average rate of change of rainfall in the rainforest between 2nd year and 6th year = 3 inches
Answer:
m times 3 = 27
b plus 4 = 13
p minus 5 = 4
Those can all be solved with 9
the other can not
Step-by-step explanation:
i hope this helped
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
2x+3(10+x)
Step-by-step explanation:
I'm not sure but I think this might be the answer
