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Ivenika [448]
3 years ago
10

12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the pr

obability that the first ball drawn is a red ball if the second ball drawn is yellow?
Mathematics
1 answer:
denis23 [38]3 years ago
8 0

Answer:

\frac{9}{35}

Step-by-step explanation:

When the first draw is done there are 9 red balls in a sample size of 21. So there probability of drawing a red ball will be \frac{9}{21}

When the second draw is done, there will be 12 yellow balls in a sample size of 20 since the first ball will not have been replaced into the bag. So the chance of someone drawing the second ball in the second draw is \frac{12}{20}

The probability of them happening in this order is the product of both probabilities:

\frac{9}{21}  * \frac{12}{20}  = \frac{9}{35}

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What is the solution to the equation
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Answer:

x = -13

Step-by-step explanation:

Distribute:

8 - 6x + 10x - 15 = 20 - 5x

Combine like terms:

4x - 7 = 20 - 5x

Isolate Variable

-x = 13

-1(-x) = -1(13)

x = -13

8 0
3 years ago
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The volume of a rectangular prism is 441 cubic cm. If the height of the prism is 11 cm, what is the area of is base? (Round to t
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Answer:

40.1 cm²

Step-by-step explanation:

V (rectangular prism) = Base area x Height

441 = BA x 11

BA = 441 / 11 = 40.1

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3 years ago
A shipping container is in the shape of a right rectangular prism with a length of 8 feet, a width of 3.5 feet, and a height of
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Step-by-step explanation:

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Scientists believe that there is an extremely massive black hole at the center of the Milky Way. How many times more massive tha
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3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
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