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saw5 [17]
3 years ago
12

Help please!! You’d have to find it algebraically!

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer: (-6,-5)

Step-by-step explanation:

2x - 2y = -2 ............ equation 1

3x - y = -13 ................ equation 2

solving by substitution method

from equation 2 , make y the subject of the formula, we have

y = 3x + 13 .............. equation 3

substitute equation 3 into equation 1 , we have

2x - 2 (3x + 13 ) = -2

2x - 6x - 26 = -2

-4x - 26 = -2

-4x = -2 +26

-4x = 24

x = 24/-4

x = -6

substitute x = -6 into equation 3 to get the value of y , we have

y = 3(-6) + 13

y = -18 +13

y = -5

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Chart:
True [87]
I would say B because it only makes since, colleges are looking for whats better in students and you will also work in groups also. So i would go with B :)
5 0
3 years ago
Use the following situation for the next few questions:
Olegator [25]

Answer:

5 oil changes.

Step-by-step explanation:

60 = 12x + 15y

60 = 12x + 15(0)

60 = 12x + 0

60

---- = x

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4 0
3 years ago
1000 was invested at 5.5% interest, compounded annually. After sometime the amount had grown to 1550. How long was the money inv
scZoUnD [109]

compound interest equation for annually compounded

A=P(1+r)^t

A=final amount

P=principal

r=rate in decimal

t=time in years


given that

A=1550

P=1000

r=5.5%=0.055

find t


1550=1000(1+0.055)^t

divide both sides by 1000

1.55=1.055^t

take ln of both sides

ln(1.55)=ln(1.055^t)

use ln rule ln(a^b)=b(ln(a))

ln(1.55)=t(ln(1.055))

divide both sides by ln(1.055)

\frac{ln(1.55)}{ln(1.055)}=t

using a calculator, we get that t=8.18544 yrs

so about 8.2yrs

4 0
3 years ago
Drag the ordered pair that are 5.5 units apart.
Alexus [3.1K]

Answer:

  (-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

  -3, -1.5, 5

The distances between pairs of these coordinates are ...

  -1.5 -(-3) = 1.5

  5 -(-3) = 8

  5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

<u>∆x = 1.5</u>

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

  30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

  √28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

__

<u>∆x = 0</u>

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

  for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

  for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

  (-1.5, -3.5) and (-1.5, 2).

6 0
3 years ago
Apply the distributive property to write an equivalent expression in factored form: 12s + 18r
Kryger [21]
The most simplified answer is the greatest factor being six. Divide both by six and six is on the outside of parentheses to be equivalent making the answer 6(2s+18r) or -6(-2s-18r) if you used negatives as I would jot down negative and positive
8 0
3 years ago
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