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nalin [4]
4 years ago
13

A cylinder cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. What is the

approximate volume of the tube? Round to the nearest whole cubic centimeter.
Mathematics
2 answers:
Gemiola [76]4 years ago
5 0

Answer:

1005 cm³ will be the volume of the cylinder cardboard tube.

Step-by-step explanation:

Diameter of a cylinder cardboard tube = 8 cm

Therefore radius = 4 cm.

Height of the cylinder cardboard tube = 20 cm.

Now we have to calculate the volume of the tube

As we know the formula of the volume of cylinder is

V = πr²h

V = π (4)²(20) = 320π cm³

Now we put the value of π as 3.14

Volume = 3.14×320 = 1004.80 ≈ 1005 cm³

Therefore Volume of the cylinder cardboard used to package a gift will be = 1005 cm³

FromTheMoon [43]4 years ago
3 0
30 i believe is your answerio
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A customer at Marty’s Fruit Stand picks a sample of 3 oranges at random from a crate containing 60 oranges, of which 4 are rotte
pychu [463]

Answer:

340 ways

Step-by-step explanation:

Given:

Total number of oranges = 60

Number of rotten oranges = 4

Number of oranges picked = 3

Now, number of good oranges = Total number - Rotten oranges

                                                    = 60 - 4 = 56

Now, we need to pick at least two rotten oranges.

So, the possible outcomes can be as follows:

  1. 2 rotten oranges + 1 good orange = 3 oranges
  2. 3 rotten oranges + 0 good orange = 3 oranges

Now, number of ways of picking 'r' distinct objects from a total of 'n' objects is given  as:

^nCr=\frac{n!}{r!(n-r)!}

Now, picking 2 rotten oranges from a total of 4 rotten oranges is:

^4C_2=\frac{4!}{2!2!}=\frac{4\times 3\times 2}{4}=6

Similarly, picking 3 rotten oranges from a total of 4 rotten oranges is:

^4C_3 =\frac{4!}{3!\times1!}=\frac{4\times 3!}{3!}=4

Now, picking 1 good orange from a total of 56 good oranges is:

^{56}C_1=56

Picking 0 good oranges means picking no good oranges.

Therefore, the total number of ways of picking at least 2 rotten oranges is the sum of the above two possibilities and is given as:

At least 2 rotten out of 3 picked = (2 rotten and 1 good) or 3 rotten

                                                       = 6 × 56 + 4

                                                       = 336 + 4 = 340 ways

Therefore, there are 340 ways of picking at least 2 rotten oranges when 3 oranges are picked from a total of 60 oranges.

8 0
4 years ago
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