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Vikentia [17]
3 years ago
7

How can you check if two fractions are equivalent?

Mathematics
1 answer:
zimovet [89]3 years ago
5 0

Step-by-step explanation:

Say you have these 2 fractions

\frac{a}{b} .........\frac{c}{d}

Cross multiply as following;

\frac{(b)(c)}{(a)(d)}=\frac{bc}{ad}

If in the end, both numerator and denominator are equal, then the fractions are equivalent.

Examples:

Example 1

\frac{20}{24}...........\frac{5}{6}

Cross multiply

\frac{(24)(5)}{(20)(6)}=\frac{120}{120}

They're equivalent.

Example 2

\frac{20}{24}........\frac{3}{4}

Cross multiply

\frac{(24)(3)}{(20)(4)} =\frac{72}{80}

They're not equivalent.

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Answer:

a

Step-by-step explanation:

7 0
3 years ago
Find the diameter of the object (6cm)
erma4kov [3.2K]

Answer:

12 cm

Step-by-step explanation:

6×2=12

6 0
3 years ago
Area of a rectangle is 42 sq inches and one side is 12 inches long what is the perimeter of the rectangle?
12345 [234]
Area if the rectangle = 42 sq. inch
Area of a rectangle = l × b
42 = 12 × b
b = 42/12 = 3.5 inch
Now, perimeter of a rectangle= 2(l + b)
= 2(12+3.5) = 2(15.5) = 31 inches
7 0
3 years ago
Make a frequency distribution and find the relative frequencies for the following number set. Round the relative frequency to th
Pani-rosa [81]

Solution: We have to find the Frequency and Relative frequency of the given data:

Frequency is the number of times a number occurs.

Relative Frequency is the number of times a number occurs divided by the total number of items.

Therefore, the frequency and relative frequency are calculated as below:

Number       Frequency          Relative Frequency

20                       1                     \frac{1}{31} \times 100 =3.2\%

21                        4                    \frac{4}{31} \times 100 =12.9\%

22                       2                    \frac{2}{31} \times 100 =6.5\%

23                       4                    \frac{4}{31} \times 100 =12.9\%

24                       3                    \frac{3}{31} \times 100 =9.7\%

25                       2                    \frac{2}{31} \times 100 =6.5\%

26                       3                    \frac{3}{31} \times 100 =9.7\%

27                       5                    \frac{5}{31} \times 100 =16.1\%

28                       3                    \frac{3}{31} \times 100 =9.7\%

29                       4                    \frac{4}{31} \times 100 =12.9\%

Total                  31

6 0
3 years ago
Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0
4 years ago
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