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nikklg [1K]
3 years ago
15

Dr. Ibanez recorded the amount of snowfall, in centimeters, at 10 different locations during 1 day and then arranged the amounts

from smallest to largest. The amounts were 3, 3, 3, 3, 4, 4, 4, 5, 5, and 6 cm. The mean of these measurements is 4 cm.
What is the mean absolute deviation?

A.
0 cm

B.
0.8 cm

C.
1 cm

D.
2.5 cm
Mathematics
2 answers:
iren2701 [21]3 years ago
7 0

Answer: the answer is b 0.8

Step-by-step explanation:

Mkey [24]3 years ago
6 0
<span>So we want to know what MAD from this set of data is that has the mean value of 4. First we determine the distance d of each number from the set from the mean value: d1=4-3=1, d2=4-4=0, d3=5-4=1, d4=6-4=2. So our set of distances is {1,1,1,1,0,0,0,1,1,2}. Now we can determine MAD: MAD=(1+1+1+1+0+0+0+1+1+2)/10=0.8.</span>
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loris [4]
1. The answer is C. cos180=-1, sin180=0. 2*(cos180+i*sin180)=2*(-1+0)=-2. Check every other answer, none of which gets -2. 

2. The answer is C. cos270=0, sin270=-1. (You can draw out these angles to see). 2*(cos270+i*sin270)=2*(0-i)=-2i, as desired. Other choices don't work.

3. Answer A. Modulus of z is \sqrt(6^2+(-6)^2)=6*\sqrt(2). <span>The </span>angle<span> of the </span>point<span> on the complex </span>plane<span> is the </span>inverse tangent<span> of the complex portion over the real portion. Theta=arctan(-6/6), and arctan(-1)=-pi/4, so theta=-pi/4=-pi/4+2pi=7pi/4. So A is the correct answer.

4. The answer is A. As above, cos270=0, sin270=-1. 3(cos270+sin270*i)=3*(0-i)=-3i. This problem is similar to question 2.

5. </span>z1 = 7(cos 40° + i sin 40°), and z2 = 6(cos 145° + i sin 145°). z1*z2=7*6*(cos 40° + i sin 40°)*(cos 145° + i sin 145°)=42*(cos40*cos145-sin40*sin145+i*sin40*cos145+i*sin145*cos40). Use formula for sum/difference formula of cosines, cos40*cos145-sin40*sin145=cos(40+145)=cos185. Again, sin40*cos145+sin145*cos40=sin(40+145)=sin185. The answer is <span>42(cos 185° + i sin 185°).</span>
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3 years ago
How do I find the missing value?
Usimov [2.4K]
Hope the given solution helps:) Have a great day. Do mark me brainliest if it has really helped you. Thank You.

4 0
2 years ago
A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
fenix001 [56]

Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

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Answer:

I Think its B

Step-by-step explanation:

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