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Dominik [7]
2 years ago
12

A line passes through the points (3,0) and (4,2). What is its equation in slope-intercept form?

Mathematics
1 answer:
N76 [4]2 years ago
3 0

Answer:

y = 2x - 6

Step-by-step explanation:

<h2>Slope intercept form:</h2>

     Equation of the line:

            \sf \boxed{ y = mx  +b}

      Here m is the slope and b is the y-intercept.

Step 1:  Find the slope

       (3 , 0) ⇒ x₁ = 3  & y₁ = 0

       (4 , 2) ⇒ x₂ = 4  &  y₂ = 2

      \sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}

                \sf = \dfrac{2 -0}{4-3}\\\\= \dfrac{2}{1}\\\\=2

<h3>      m = 2</h3>

Step2: Now, substitute the value of 'm' in the equation.

    y = 2x + b

Step3: In the above equation plug in any point. Here, (3 ,0) is chosed.

      0 = 2*3 + b

      0 = 6 + b

      -6 = b

<h3>      b = -6</h3>

Step4: Equation of the line:

<h3>           y = 2x - 6</h3>

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