What's the solution to 1/5+1/3x>1/2-1/4?

Mathematics

1 answer:

Serjik [45]3 years ago

6 0

Answer:

x> 3/20

Step-by-step explanation:

Let's solve your inequality step-by-step.

1 /5 + 1 /3 x> 1 /2 − 1 /4

Step 1: Simplify both sides of the inequality.

1 /3 x+ 1 /5 > 1 /4

Step 2: Subtract 1/5 from both sides.

1 /3 x+ 1/ 5 − 1 /5 > 1 /4 − 1 /5 1 /3 x> 1 /20

Step 3: Multiply both sides by 3.

3*( 1 /3 x)>3*( 1 /20 ) x> 3 /20

Answer:

x> 3/ 20

Hope this helps!!

You might be interested in

Find the number that completes the equation.

Alja [10]

What you have to do is multiply 5 on each sides on the equation. Next, you cross out the 2 gives on the left side. Bring down the 6+y and 6 times 5 equals 30. So your equation would be 6+y=30. Then, you subtract 6 from both sides and cross out the 6’s on the left side... Bring down your “y” and 30-6=24. So y=24

5 0

2 years ago

One number is 2/5 of another number. the sum of the two numbers is 35. find the two numbers. use a comma to separate your answer

Ivan

We have x = (2/5)y and x + y = 35;
then, (2/5)y + y = 35;
2y + 5y = 175;
7y = 175;
y = 27;
x = 35 - 27;
x = 8;

4 0

2 years ago

A basketball player makes 17 of the 25 shots she takes. What percentage of shots did she successfully make?

Mumz [18]

Percentage of successful shots = 14/25 x 100 = 56%

Answer: 56%

5 0

2 years ago

Read 2 more answers

The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation

Paraphin [41]

Answer:

0.13% of students have scored less than 45 points

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 60, \sigma = 5$