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ipn [44]
3 years ago
15

The probability of pulling an orange is 2 out of 5 if I 20 times how many of them would be orange

Mathematics
1 answer:
telo118 [61]3 years ago
4 0
The answer would be 8.
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in a favorite punch mix there are 3 parts orange juice, 2 parts pineapple juice and 1 part ginger ale. How many quarts of each w
juin [17]
Number of parts of the drinks = 31+1 = 6

In a 30 quart mixture:-

amount of orange juice = 3/6 + 30  =  15 qrts
   ....  ... ...  pineapple    = 2/6 * 30   =  10 qrts
  ....  ......... ginger ale    = 1/6 * 30  =    5 qrts
8 0
3 years ago
Read 2 more answers
Find the measure of x for this shape.<br><br>A. 36<br>b.28<br>c.32<br>d.22
love history [14]

let's recall that in an isosceles triangle, the twin sides make twin angles at the bottom/base, so on the triangle on the left-side, if the "vertex" atop has an angle of 116°, then the twin sides below are simply 180° - 116 = 64, split that in half and that's 32° each.

The same is true for the isosceles triangle on the right side.  Also recall that a flat-line is always 180°, 32 + 72 + 76 = 180.

Check the picture below.

4 0
3 years ago
A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh
solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

7 0
3 years ago
Complete the square on the following quadratic x2+10x+9=0
kakasveta [241]
Given a quadratic equation x^{2} +ax+c=0

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + 5^{2} and - 5^{2} to the expression:

x^{2} +2*5*x+ 5^{2} -5^{2}+9=0

(x^{2} +2*5*x+ 5^{2}) -25+9=0

(x+5)^{2}-16=0



Answer: (x+5)^{2}-16=0
8 0
3 years ago
What two numbers can you multiply to get 5 and add to get 8
Mashcka [7]
1 x 5 = 5 + 3 = 8
tell me if it’s not the answer your looking for
5 0
3 years ago
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