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Flauer [41]
3 years ago
11

A man completes 10 laps of a circular track with a radius of 4.5 metres (when rounded to one decimal place). Find the minimum an

d maximum distance that he runs
Mathematics
1 answer:
il63 [147K]3 years ago
5 0
Circumference of a circle: 2<span>πr

Simply input the radius, multiply the answer by 10 (because the man runs 10 laps) and solve!

Distance traveled = (</span>2πr) 10
                               = 2π(4.5m) 10
                               = ~ 282.743m

Hope this helps!
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How do you solve x for (x+5)^3/2 = ( x-1)^3
malfutka [58]

Answer:

x = 6 (2^(1/3) + 2^(2/3)) + 7 or x = 6 (-2)^(1/3) ((-1)^(1/3) - 2^(1/3)) + 7 or x = 6 (-2)^(1/3) ((-2)^(1/3) - 1) + 7

Step-by-step explanation:

Solve for x:

1/2 (x + 5)^3 = (x - 1)^3

Expand out terms of the right hand side:

1/2 (x + 5)^3 = x^3 - 3 x^2 + 3 x - 1

Subtract x^3 - 3 x^2 + 3 x - 1 from both sides:

1 - 3 x + 3 x^2 - x^3 + 1/2 (x + 5)^3 = 0

Expand out terms of the left hand side:

-x^3/2 + (21 x^2)/2 + (69 x)/2 + 127/2 = 0

Bring -x^3/2 + (21 x^2)/2 + (69 x)/2 + 127/2 together using the common denominator 2:

1/2 (-x^3 + 21 x^2 + 69 x + 127) = 0

Multiply both sides by 2:

-x^3 + 21 x^2 + 69 x + 127 = 0

Multiply both sides by -1:

x^3 - 21 x^2 - 69 x - 127 = 0

Eliminate the quadratic term by substituting y = x - 7:

-127 - 69 (y + 7) - 21 (y + 7)^2 + (y + 7)^3 = 0

Expand out terms of the left hand side:

y^3 - 216 y - 1296 = 0

Change coordinates by substituting y = z + λ/z, where λ is a constant value that will be determined later:

-1296 - 216 (z + λ/z) + (z + λ/z)^3 = 0

Multiply both sides by z^3 and collect in terms of z:

z^6 + z^4 (3 λ - 216) - 1296 z^3 + z^2 (3 λ^2 - 216 λ) + λ^3 = 0

Substitute λ = 72 and then u = z^3, yielding a quadratic equation in the variable u:

u^2 - 1296 u + 373248 = 0

Find the positive solution to the quadratic equation:

u = 864

Substitute back for u = z^3:

z^3 = 864

Taking cube roots gives 6 2^(2/3) times the third roots of unity:

z = 6 2^(2/3) or z = -6 (-1)^(1/3) 2^(2/3) or z = 6 (-2)^(2/3)

Substitute each value of z into y = z + 72/z:

y = 6 2^(1/3) + 6 2^(2/3) or y = 6 (-1)^(2/3) 2^(1/3) - 6 (-1)^(1/3) 2^(2/3) or y = 6 (-2)^(2/3) - 6 (-2)^(1/3)

Bring each solution to a common denominator and simplify:

y = 6 (2^(1/3) + 2^(2/3)) or y = 6 (-2)^(1/3) ((-1)^(1/3) - 2^(1/3)) or y = 6 (-2)^(1/3) ((-2)^(1/3) - 1)

Substitute back for x = y + 7:

Answer: x = 6 (2^(1/3) + 2^(2/3)) + 7 or x = 6 (-2)^(1/3) ((-1)^(1/3) - 2^(1/3)) + 7 or x = 6 (-2)^(1/3) ((-2)^(1/3) - 1) + 7

7 0
3 years ago
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Graph -5, 0, 2,and 4 on a numberline
Elena-2011 [213]

Answer:

That's the way it should be graphed

4 0
3 years ago
Point U has Coordinates (-5,1) and point V has coordinates (7,9) find the coordinates of the midpoint of UV
frutty [35]

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

Midpoint of a Line Segment:

A line segment's midpoint is a point that divides the line segment across two equal sections. The midpoint of a line segment with coordinates at both ends X₁ , Y₁ and  X₂, Y₂ is calculated using:

<h3>According to the given data:</h3>

Point U has Coordinates (-5,1).

point V has coordinates (7,9).

Find  coordinates of the midpoint of UV = ?

We know that to find Midpoint of a Line Segment:

                               = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Where U

           X₁ = -5

           Y₁ = 1

Whare V

           X₂ = 7

           Y₂ = 9

Putting the value in the formula:

UV = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

       = (-5 + 7)/2 , (1 + 9)/2

       = -6 , 5

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

To know more about Midpoint of a Line Segment visit:

brainly.com/question/13792156

#SPJ9

4 0
1 year ago
7th grade math help me please :)
netineya [11]

Answer:

the second

Step-by-step explanation:

8 0
3 years ago
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A dilation changes the size AND the shape of a figure
dolphi86 [110]
False, it does not change the shape of the figure, it only changes the size
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