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Degger [83]
2 years ago
5

Steve has a regular deck of playing cards. He wants to know the probability of pulling two clubs from the deck in a row without

replacing the first club. What is the probability ? A. 1/52 B. 6% C. 12/51 D. 24% E. 13/52
Mathematics
1 answer:
Murrr4er [49]2 years ago
8 0
Es la D por que eso ya lo hice yo
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What’s the volume of 4.3ft 5.2ft cone round to nearest hundredth
Vika [28.1K]

Answer:

Pick the best solution.

Step-by-step explanation:

Volume of a cone is V = ⅓πr²h

If cone diameter is 4.3

V = ⅓π(4.3/2)²(5.2) = 25.17148... ≈ 25.17 ft³

If cone radius is 4.3

V = ⅓π(4.3)²(5.2) = 100.685950... ≈ 100.69 ft³

If cone diameter is 5.2

V = ⅓π(5.2/2)²(4.3) = 30.439938... ≈ 30.44 ft³

If cone radius is 5.2

V = ⅓π(5.2)²(4.3) = 121.75975... ≈ 121.76 ft³

5 0
3 years ago
Noah picked 3 kilograms of cherries. Mai picked half as many cherries as Noah. How many total kilograms of cherries die Mia and
Angelina_Jolie [31]

it would be 4.5 total

6 0
3 years ago
11. 8 cars are in the parking lot. Then 6 more cars come. How many cars are there now? 12.stretch your thinking. Look at the sto
Sholpan [36]

Answer:

#11 : 14 cars

#12 : 8+6+4=18

Step-by-step explanation:

8 0
3 years ago
Given right triangle MNL what is the value of cos(M)?
FromTheMoon [43]

Step 1

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

ML^{2} =NL^{2} +MN^{2}

Solve for MN

MN^{2}=ML^{2} -NL^{2}

in this problem

ML=25\ units\\ NL=15\ units

Substitute in the formula above

MN^{2}=25^{2} -15^{2}

MN^{2}=400

MN=20\ units

Step 2

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}

adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units

Substitute

cos (M)=\frac{20}{25}

cos (M)=\frac{4}{5}

cos (M)=0.8

therefore

The answer is

The value of cos(M) is equal to 0.8


6 0
3 years ago
Please help with this question<br> (10a³+20a²-5a)
grigory [225]
Factoring the expression would be 6a(2a^2+4a-1)
8 0
3 years ago
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