We are given a diagram with different rays and lines.
Note: A line can be extend more and more upto infinitely length from both of the ends but a ray can be extend from from end only.
We need to find the rays for the line BE.
We can see BE line has a point A in between line.
So, we can name the rays formed with end point A as AB and AE.
<h3>Therefore, AB and AE rays are part of line BE.</h3><h3>So, the correct option is 2nd option :</h3><h3>AB and AE.</h3>
Answer:
x=27
Step-by-step explanation:
180-2x-40+180-3x+180-x-50+180-4x = 360
360-2x-40-3x+360-x-50-4x= 360
360-10x-90= 0
10x= 270
x= 27
The corporate team building event will cost $18.00 because $2 multiplied by 6 is $12.00 and $1.00 multiplied by 6 is $6.00 and 6 plus twelve is 18 so it would be $18.00
Answer:
Step-by-step explanation:
Given that t A, B, and C are invertible matrices of the same
size.
To pr that 
to pr that 
LS=
Thus proved
You can say that the slope is negative. A line on a graph that goes from the upper left corner to the bottom right is a negative slope.