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Nesterboy [21]
3 years ago
14

Write an expression to show how many meters are equivalent to x centimeters

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0
1 meter is 100 centimeters so...

x meters are equal to 100x centimeters
Roman55 [17]3 years ago
5 0
Y=meters
x=centimeters

Y=100x
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What is the equation of this line in standard form
Anestetic [448]

Answer:

6x-11y=-13

Step-by-step explanation:

(x1,y1)=(3/2,2) and (x2,y2)=(-4,-1)

y-y1= y2-y1/x2-x1 (x-x1)

y-2=-3/-11/2(x-3/2)

=6/11(x-3/2)

11(y-2)=6x-9

11y-22=6x-9

6x-11y=9-22

6x-11y=-13

7 0
3 years ago
A person borrows $50000 loan from bank at a rate of 10% for 5 years compounded yearly.
Hatshy [7]
<h3>Given:</h3>
  • P= $50,000
  • R= 10%
  • T= 5 years
<h3>Note that:</h3>
  • P= Principal amount
  • R= Rate of interest
  • T= Time period
<h3>Solution:</h3>

\large\boxed{Formula: A= P(1+ \frac{R}{100}{)}^{T}}

Let's substitute according to the formula.

A= 50000(1+ \frac{10}{100}{)}^{5}

<em>A=</em><em> </em><em>$80525.5</em>

Now, we can find the interest paid

\large\boxed{I= A-P}

We'll have to deduct the total amount from the principal amount.

Let's substitute according to the formula.

I= 80525.5-50000

<em>I=</em><em> </em><em>$30525.5</em>

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>amount</u><u> </u><u>paid</u><u> </u><u>after</u><u> </u><u>5</u><u> </u><u>years</u><u> </u><u>is</u><u> </u><u>$</u><u>80525.5</u><u> </u><u>and</u><u> </u><u>$</u><u>30525.5</u><u> </u><u>was</u><u> </u><u>paid</u><u> </u><u>as</u><u> </u><u>interest</u><u>.</u>

7 0
2 years ago
Jasmine's cell phone company charges her $35 an month for phone service plus 0.50 for each text message.How many text messages d
VashaNatasha [74]

Jasmine sent 17 texts. 0.50×34=17

17=35=52

6 0
3 years ago
On a standardized test with a normal distribution the mean score was 67.2. The standard deviation was 4.6. What percent of the d
Reika [66]

Answer:

P ( -1 < Z < 1 ) = 68%

Step-by-step explanation:

Given:-

- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :

                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

                         X~ N ( 67.2 , 4.6^2 )

Find:-

What percent of the data fell between 62.6 and 71.8?

Solution:-

- We will first compute the Z-value for the given points 62.6 and 71.8:

                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:

                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

6 0
3 years ago
I can add fractions with unlike denominators. 2/5 + 3/10 =​
slava [35]

Answer:

7/10

Step-by-step explanation:

2/5 multiply the denominator by 2 which will make it 10. Then multiply the numerator by 2 which will make it 4. So it will be 4/10. Then add 4/10 to 3/0 which makes 7/10.

6 0
3 years ago
Read 2 more answers
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