3 years ago

Explain how to solve 4|3x-1|+1=8

Mathematics

1 answer:

denis-greek [22]3 years ago

8 0

4|3x - 1| + 1 = 8

4|3x - 1| = 8 - 1

4|3x - 1| = 7

|3x - 1| = 7/4

Now lets think, we have 3x - 1 in module, so either its 7/4 or -7/4, we will have 7/4 at the end because of it, so we may have 2 solutions in this case:

3x - 1 = 7/4

and

3x - 1 = -7/4

So let's see:

3x - 1 = 7/4

3x = 7/4 + 1

3x = 11/4

x = 11/12

3x - 1 = -7/4

3x = -7/4 + 1

3x = -3/4

x = -1/4

So we have two possible answers, x = 11/2 and x = -1/4

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Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

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BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

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Divide both sides by 2.

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Now,

$m\angle DBC=(x+20)^\circ$

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$m\angle ABC=(3x)^\circ+(x+20)^\circ$

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3 years ago

Explain how to solve 4|3x-1|+1=8​

Explain how to solve 4|3x-1|+1=8