A restaurant has a special whereby both parents can eat for $20 and each child can eat for $5. Assuming a family group consists of both parents and at least one child, what is the maximum number of family groups that could have attended given that the restaurant took $115?
2 answers:
4groups of adults and 7 kids
The answer is 2.55555555555556 This is because there are 2 parents so 20 * 2 = 40 We have 1 child. = 5 = 45 So 115 / 45= 2.55555555556 I hope this helps and please make this the Brainliest answer. :)
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Answer:
127
Step-by-step explanation:
400+1495=1895
1895/15=126.333333333
It will be a J-shaped graph. As X increases, Y will increase at a sharper rate, so it will look exactly like a J when graphed
The answer is D! if you sub them in :)
I am pretty sure your correct answer is 3380.
Find a common denominator the common denominator of 7 and 3 is 21 2/21 - 3/21 change the numerator 14/21 - 9/21 =5/21