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julsineya [31]
3 years ago
9

A restaurant has a special whereby both parents can eat for $20 and each child can eat for $5. Assuming a family group consists

of both parents and at least one child, what is the maximum number of family groups that could have attended given that the restaurant took $115?
Mathematics
2 answers:
nordsb [41]3 years ago
5 0
 4groups of adults and 7 kids 
vodomira [7]3 years ago
3 0
The answer is 2.55555555555556
This is because there are 2 parents so 20 * 2 = 40 We have 1 child. = 5 
= 45
So 115 / 45= 2.55555555556
I hope this helps and please make this the Brainliest answer.
:)

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Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab
zhenek [66]

Answer:

test statistic is ≈ -0.36

p-value is  ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • sample mean driving distance (233.8 yards)
  • M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
  • s is the standard deviation (46.6 yards)
  • N is the sample size (192)

Then test statistic is z=\frac{233.8-235}{\frac{46.6}{\sqrt{192} } } =-0.3568

p-value is  0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

6 0
4 years ago
Help me please I don’t understand
ankoles [38]
A² + b² = c²
8² + x² = 16²
x² = 16² - 8²
x² = 192
x =√192
x =8√3
5 0
4 years ago
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3 + 5x - kx = y <br><br> (what’s the value of x)
lesya [120]
X = Y - 3 / 5 - k hope this helps
8 0
3 years ago
Determine the total number of proper subsets of the set of letters from the English alphabet a,b, c, ...,j. The number of proper
Inga [223]
\{a,b,c,\ldots,j\} has ten elements, so any proper subset has at most nine of these elements.

The number of ways of taking any 0\le n\le 9 letters from this set is given by the binomial coefficient,

\dbinom{10}n=\dfrac{10!}{n!(10-n)!}

and in particular, the total number of ways to picking proper subsets is

\displaystyle\sum_{n=0}^9\binom{10}n=\dbinom{10}0+\dbinom{10}1+\cdots+\dbinom{10}9

Without computing each term directly, let's instead use a direct result from the binomial theorem, which says

\displaystyle\sum_{n=0}^N\binom Nna^nb^{N-n}=(a+b)^N

If we replace a=b=1, then we're left with

\displaystyle\sum_{n=0}^N\binom Nn=(1+1)^N=2^N

We can use this to evaluate our sum directly:

\displaystyle\sum_{n=0}^9\binom{10}n=\sum_{n=0}^{10}\binom{10}n-\binom{10}{10}=2^{10}-1=1023
8 0
3 years ago
√75+√3 can you show me the work to solve ​
vitfil [10]

Answer:

6 \sqrt{3}

Step-by-step explanation:

You need to factor out the greatest perfect square factor possible.

\sqrt{75} + \sqrt{3} =

= \sqrt{25 \times 3} + \sqrt{3}

= \sqrt{25} \times \sqrt{3} + \sqrt{3}

= 5 \sqrt{3} + \sqrt{3}

= 6 \sqrt{3}

8 0
3 years ago
Read 2 more answers
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