Identify all the points that are on the following quadratic function: y = x^2

Simplify. Rewrite the expression in the form b^n. b^10/b^6

Vlad1618 [11]

Answer:

<h2>The answer is b⁴</h2>

Step-by-step explanation:

$\frac{ {b}^{10} }{ {b}^{6} }$

Using the rules of indices

That's

$\frac{ {a}^{x} }{ {a}^{y} } = {a}^{x - y}$

Since the bases are the same and are dividing we subtract the exponents

So we have

$\frac{ {b}^{10} }{ {b}^{6} } = {b}^{10 - 6}$

We have the final answer as

Hope this helps you

6 0

3 years ago

Read 2 more answers

Round each number to the nearest tenth.

avanturin [10]

122.1 or 122
becuase the original answer is 122.13 and the 3 gets out becuase it rounds down and so does the 1

4 0

3 years ago

Read 2 more answers

a sequence of numbers begins at 400. If the pattern increases by consecutive multiples of 5 starting with 5, then find the next

bazaltina [42]

Given :

A sequence of numbers begins at 400.

To Find :

If the pattern increases by consecutive multiples of 5 starting with 5, then find the next 3 numbers in the sequence 400, ___, ___, ___ .

Solution :

This is the a question of arithmetic progression .

The first term is , a = 400 .

Now , it is given that the next numbers increase by the multiples of 5 starting with 5 .

So , common difference is , d = 5 .

Now , we know , $n^{th}$ number in A.P is given by :

$a_n=a+(n-1)d$

Putting value of n = 2 , 3 , 4 .

We get :

$a_2=a+(2-1)d=400+5=405\\\\a_3=a+(3-1)d = 400 + (5\times 2) = 410\\\\a_4=a+(4-1)d = 400 +(5\times 3)=415$

Therefore , the next 3 numbers in the sequence is 400 , 405 , 410 , 415 .

Hence , this is the required solution .

8 0

3 years ago

. i will give brainliest.A man is 26 years older than his son. He is also 8 years older than three times his son’sage.

Shkiper50 [21]

Step-by-step explanation:

Let the son's age be x and man be y

y=26+x

y=8+3x

x=9

Son's age is 9

6 0

3 years ago

Read 2 more answers

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Identify all the points that are on the following quadratic function: y = x^2 - 3x