Suppose two bicyclists start at the same location.

Mathematics

1 answer:

DerKrebs [107]2 years ago

5 0

Answer:

Step-by-step explanation:

See attachment.

If both cyclists travel for the same time and speed, they will have travelled the same distance. Since one is headed north and the other east, we can see that the distance between them in one hour is the hypotenuse of a right triangle. Each leg has distance x. We can say x^2 + x^2 = (3 $\sqrt{2}$ )^2

2x^2 =1 8

x^2 = 9

x = 3

They both rode 3 miles.

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2 years ago

WILL MARK BRAINLIEST!!! NEED THIS ASAP!!

DiKsa [7]

Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

We will be using Pythagoras theorem to solve this problem. This is as this problem forms a right-angle triangle. Pythagoras theorem is the following:

a^2 + b^2 = c^2

Where c = hypotenuse of right-angle triangle

Where a and b = other two sides of right-angle triangle

To begin with, we will substitute the values from the problem into the equation. Then we will make the height of the tree the subject of the equation.

a = height of tree = ?

b = distance from the bird on the ground to the base of the tree = 8 metres

c = distance bird travelled from the ground to the top of the tree = 9 metres

a^2 + b^2 = c^2

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a = square root of ( 9^2 - 8^2 )

a = square root of ( 81 - 64 )

a = square root of ( 17 )

a = 4.123...

a = 4.1 ( rounded to the nearest tenth )

FINAL ANSWER:

Therefore, the height of the tree is 4.1 metres ( rounded to the nearest tenth ).

Hope this helps! :)
Have a lovely day! <3

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2 years ago

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Thepotemich [5.8K]

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