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ladessa [460]
2 years ago
14

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to(g*h)(5)? a (5 – 7)2, b (5)2 – 7, c (5)2(5 – 7), d (5 – 7)x2

Mathematics
1 answer:
asambeis [7]2 years ago
8 0
H(x) = x - 7
g(x) = x^2
(g * h)(x) = x^2 (x - 7)
(g * h)(5) = 5^2 (5 - 7)
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What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
How many quarts of paint if wall is 10 feet long and 8 feet tall and want to cover 50 square feet?
finlep [7]
300 quarts i think
ok
4 0
3 years ago
2 6/7 x 2 4/5 asnwer
zhannawk [14.2K]
8

20/7 times 14/5 = 8




7 0
3 years ago
Which situation can be represented by the<br> inequality 4x − 25 &lt; 125?
GaryK [48]
First add 25 to both sides of the inequality.
You get 4x < 150
Now divide both sides by 4.
You get x < 37.5
So x can be anything less than 37.5,  such as 36,  35 or 34.
8 0
3 years ago
An electronics store makes a profit of $72 for every standard CD player sold and $90 for every portable CD sold. the managers ta
Alisiya [41]

s -> no: of standard CD players sold

p -> no: of portable CD players sold.

Profit Per Standard CD player=72$

Profit per Portable CD player =90$

Target Amount =360$

<em>I</em><em>n</em><em> </em><em>short</em><em>:</em><em> </em><em>The</em><em> </em><em>combined</em><em> </em><em>sales</em><em> </em><em>of</em><em> </em><em>Both</em><em> </em><em>the</em><em> </em><em>CD</em><em> </em><em>player</em><em>'s</em><em> </em><em>must</em><em> </em><em>exceed</em><em> </em><em>or</em><em> </em><em>atleast</em><em> </em><em>become</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>3</em><em>6</em><em>0</em><em>$</em><em> </em><em>to</em><em> </em><em>a</em><em>c</em><em>q</em><em>u</em><em>i</em><em>r</em><em>e</em><em> </em><em>the</em><em> </em><em>target</em><em>.</em>

<em>Thus</em><em>;</em><em> </em><em>the</em><em> </em><em>inequality</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>stated</em><em> </em><em>as</em><em>:</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>7</em><em>2</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>9</em><em>0</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em>3</em><em>6</em><em>0</em>

<em>-</em><em>></em><em> </em><em>3</em><em>6</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>4</em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em>1</em><em>8</em><em>0</em>

<em>-</em><em>></em><em> </em><em>1</em><em>2</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em>1</em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em> </em><em>9</em><em>0</em>

<em> </em><em> </em><u><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em></u>

<em>-</em><em>></em><u>|<em> </em><em>4</em><em>(</em><em>s</em><em>)</em><em> </em><em>+</em><em> </em><em>5</em><em>(</em><em>p</em><em>)</em><em> </em><em>≥</em><em> </em><em>3</em><em>0</em><em> </em><em> </em><em> </em><em> </em>|</u>

<em><u>Hope it helps...</u></em>

<em><u>Hope it helps...Regards;</u></em>

<em><u>Hope it helps...Regards;Leukonov/Olegion.</u></em>

8 0
3 years ago
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