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Lilit [14]
4 years ago
12

12. Determine the shortest distance from the

Mathematics
1 answer:
Mnenie [13.5K]4 years ago
7 0

Answer:

\large\boxed{d=\dfrac{31\sqrt{34}}{34}\approx5.32}

Step-by-step explanation:

The formula of a distance between a point (x₀, y₀) and a line Ax + By + C = 0:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}

We have the point D(5, 4) and the line 3x + 5y - 4 = 0.

Substitute:

x_0=5,\ y_0=4,\ A=3,\ B=5,\ C=-4

d=\dfrac{|(3)(5)+(5)(4)-4|}{\sqrt{3^2+5^2}}=\dfrac{|15+20-4|}{\sqrt{9+25}}=\dfrac{|31|}{\sqrt{34}}\cdot\dfrac{\sqrt{34}}{\sqrt{34}}=\dfrac{31\sqrt{34}}{34}

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