The event "Atleast once" is the complement of event "None".
So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.
At Morning, the probability that Marvin does not teleport = 2/3
Likewise, the probability tha Marvin does not teleport during evening is also 2/3.
Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.
So, the probability that Marvin does not teleport during the day = 
Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.
Probability that Marvin teleports atleast once during the day = 
The answer is 96*5 =480 so nancy will call 480 people in a 5 day workweek
I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form
Answer:
Yes, he earned a Varsity letter because he played in 61% of the games.
Step-by-step explanation:
To know the percent of games he played out of the total, we can do it by dividing the games he played by the total of games and multiply this by 100% to get the percent of games he played:

We solve:
0.611111*100% = 61.11%
So we know that he earned a letter because he played in 61.11% of the games, more than he needed.