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oksian1 [2.3K]
3 years ago
10

The jaeger reading cards are used to test _____ vision

Chemistry
1 answer:
aleksley [76]3 years ago
3 0
The Jaeger reading cards are used to test near vision. It's usually held by a patient at a certain distance from the eye depending on the size being read. The smallest letters one can read is what determines their visual acuity!
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Which is the correct Lewis dot structure of NH2-?
enot [183]

Answer:

A

Explanation:

because it can share and remain with ither electrons

5 0
3 years ago
Which has a larger atomic radius, F or F-?
NeX [460]

F- due to the fact that it has one more electron.


Hope this helps and good luck :)

7 0
3 years ago
Read 2 more answers
What is the mass if the weight is 410 N?Solution410/10=______kg
3241004551 [841]

Answer:

41

Explanation:

w = mg

m = w/g

m = 410/10

= 41

4 0
2 years ago
Chandra wants to know how many moles are contained in 150.0 g ccl4 (carbon tetrachloride). what quantity of ccl4 should she use
Fynjy0 [20]

The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CCl₄</h3>
  • Mass of CCl₄ = 30 g
  • Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
  • Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 150 / 154

Mole of CCl₄ = 0.974 mole

Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.

Learn more about mole:

brainly.com/question/13314627

#SPJ4

8 0
2 years ago
BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:
stepladder [879]

C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that  

<em>In a closed system, the masses before and after the reaction are the same </em>

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

mass O = 32 : 2 = 16 g

H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

Mass of a single C :

\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12

7 0
3 years ago
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