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4 years ago

The jaeger reading cards are used to test _____ vision

1 answer:

3 0

The Jaeger reading cards are used to test near vision. It's usually held by a patient at a certain distance from the eye depending on the size being read. The smallest letters one can read is what determines their visual acuity!

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The statement 2 2 = 4 would be considered a _____ in the science world

mars1129 [50]

The statement would be considered a law.

4 0

3 years ago

Read 2 more answers

What is it called when energy is lost or removed?

enot [183]

I think it would be ionization

7 0

3 years ago

A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O3(g)+NO(g)⟶O2(g)+NO2

julsineya [31]

Answer:

Initial rate of reaction is $2.07\times 10^{-3}M.s^{-1}$ .

Explanation:

It is a second order reaction.

Initial rate of reaction = $k[O_{3}]_{0}[NO]_{0}$ , where k is rate constant, $[O_{3}]_{0}$ is the initial concentration of $O_{3}$ and $[NO]_{0}$ is the initial concentration of NO.

Here, k = $4.09\times 10^{6}M^{-1}.s^{-1}$ , $[O_{3}]_{0}=5.84\times 10^{-6}M$ and $[NO]_{0}=8.65\times 10^{-5}M$

So, initial rate of reaction = $(4.09\times 10^{6}M^{-1}.s^{-1})\times (5.84\times 10^{-6}M)\times (8.65\times 10^{-5}M)$

= $2.07\times 10^{-3}M.s^{-1}$

So, initial rate of reaction is $2.07\times 10^{-3}M.s^{-1}$

8 0

3 years ago

Which cell organelle is where proteins are made? A. nucleus B. ribosome C. vacuole D. mitochondrion

N76 [4]

Answer:

B. ribosome

Explanation:

In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.

5 0

4 years ago

Read 2 more answers

B. the radioactive atom decays by alpha emission. write an equation showing the decay. (1 point)

zalisa [80]

alpha decay is an emission of ₂⁴He nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

Let's assume that the parent atom is X, atomic number is z and mass number is A. Then the formed daughter nucleus, Y should have atomic number as z-2 and mass number as A-4.

The equation is

(z) (A)X → ₂⁴α + (z-2)(A-4)Y

Example:

₉₄²³⁹Pu → ₂⁴α + ₉₂<span>²³⁵U</span>

7 0

3 years ago