In this problem, since we are trying to find Sam's monthly net income, we just need to multiply his weekly net income (which is after all the deductions come out) by how many times he gets paid! Because he gets paid 4 times, we just need to multiply $654.48 by 4! The you should get an answer of $2617.92, which is Sam's monthly net income!
Answer:
K must be in range <u>$45000 ≤ k ≤ $53000 </u>to make this an effective screening device.
Step-by-step explanation:
In order for the screening device to be effective, the range of k must be such that, it is more than the pay of a worker without diploma. The extra amount must at least be equal to the cost of diploma
So the value of k must be in range from (35000 + 10000) to (35000 + 18000)
Hence,
<u>$45000 ≤ k ≤ $53000</u>
Answer: X = 27
Step-by-step explanation: If we observe very closely, we have two similar triangles in the diagram. The first one is ABC and the other triangle is EDC. Also take note that angle ACB in the first triangle is equal in measurement to angle ECD (45 degrees) in the other triangle, (Opposite angles).
Hence in triangle ECD, we have identified two angles so far which are angle 2x + 10 and angle 45. Same applies to triangle ABC, we already have two angles which are, 3x - 10 and 45.
However angle D in the second triangle is equal in measurement to angle B in the first triangle
(Alternate angles).
Hence we have a third angle in triangle ABC which is
Angle B = 2x + 10.
Therefore 3x - 10 + (2x + 10) + 45 = 180
(Sum of angles in a triangle)
3x - 10 + 2x + 10 + 45 = 180
By collecting like terms we now have
3x + 2x = 180 + 10 - 10 - 45
5x = 135
Divide both sides by 5,
x = 27
The correct way to move the decimal to find the quotient is b. two places to the right.
This is because 100 has two zeroes in it, so you know that you have to move the decimal either two places to the right or two places to the left.
100 is a positive number, and when multiplied by a positive number with a decimal, it makes an even larger number. So, you would move 23.8 decimal place two places to the right.
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:

The z-score for 1.5 flaws per square yard is:

The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.