Answer:
<em>2 solutions</em>
Step-by-step explanation:
Given the expression
2m/2m+3 - 2m/2m-3 = 1
Find the LCM of the expression at the left hand side:
2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1
open the bracket
4m²-6m-4m²-6m/(4m²-9) = 1
Cross multiply
4m²-6m-4m²-6m = 4m² - 9
-12m = 4m² - 9
4m² - 9+12m = 0
4m² +12m-9 = 0
<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>
Answer:
M, Z
O, X
P, W
N, Y
Step-by-step explanation:
They are all Alternate Exterior Angles.
<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!</em>
The awser for this problem im preety sure is going to be aswer c
Answer:
68%
Step-by-step explanation:
25-8=17
17/25=0.68
68%
Hope this helped :)
Step-by-step explanation:
The formula of a volume of a pyramid:

B - base area
H - height
H - height of pyramids
Pyramid A:


Pyramid B:



The volume of the pyramid A is twice as large as the volume of the pyramid B.
The new height of pyramid B: 2H
The new volume:

The volume of the pyramid A is equal to the volume of the pyramid B.