Ask question

Ask question

All categories

2 years ago

15

Derivative of the (sqrt of t/4t-3)

1 answer:

Soloha48 [4]2 years ago

3 0

Next time, please enclose the function in the denominator inside parentheses.

Derivative of the (sqrt of t/4t-3) should be
<span>
Derivative of the (sqrt of t/[4t-3])

then f(t) = sqrt( t / [4t-3] ), or f(t) = ( t/ [4t-3])^(1/2)

Use the power rule here. f '(t) = (1/2) [ t/{4t-3} ]^(-1/2) times the derivative of [ t / (4t-3) ]. Can you finish this differentiation?

</span>

You might be interested in

Rama09 [41]

Answer:

a. 48

b. You need 6 packs of cups and 8 packs of plates

c. 72 is another one she would need 9 packs of cups and 12 packs of plates to get this one

6 0

2 years ago

Read 2 more answers

Find the perimeter of the figure. Round all figures to the nearest hundredths place. Isosceles trapezoid

zhannawk [14.2K]

Answer:

d. 92.84

Step-by-step explanation:

The top edge overhangs the bottom edge by (39 -27)/2 = 6 ft on both ends. This makes the slant side have length

.. √((6 ft)^2 +(12 ft)^2) = 6√5 ft

Then the perimeter is

.. (39 +6√5 +27 +6√5) ft = 66 +12√5 ft

= 92.83 ft

6 0

3 years ago

R is in the middle of pqs btw

Vlad [161]

Answer:

46

Step-by-step explanation:

5x = 3x - 2 + 34

5x = 3x + 32

2x = 32

x = 16

plug back in

3( 16 ) - 2

48 - 2

46

5 0

3 years ago

plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi

erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar $= length \times width\times height$

Plugging the values in the equation we get,

Volume of the gold bar $=18.00 \times 9.21 \times 4.45= 737.721cm^3$

Now that we have the volume we can find the mass by using the formula,

$Mass= density \times volume$

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

$Mass = 19.32\times 737.721=14252.769$ grams

So, the mass of the gold bar is 14252.769 grams

7 0

3 years ago

Which ordered pair is on the graph of the function y = 8x - 1 ?

Kobotan [32]

It is b Bc if you actually look at the other one it don’t make sense

4 0

3 years ago