9514 1404 393
Answer:
Step-by-step explanation:
There are a couple of relations that are applicable to these questions.
- the product of segment lengths of crossed chords is the same for both chords
- the angle formed at crossed chords is the average of the intercepted arc measures
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The segment lengths relation tells us ...
10x = 8×7 . . . . . . products of segment lengths are equal
x = 56/10 = 5.6 . . . . divide by 10
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The value of y° is the average of the intercepted arcs:
y° = (85° +45°)/2 = 65°
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<em>Additional comment</em>
This diagram does not have enough information to allow computation of z. We would need to know the intercepted arc, or the length of the secant that meets tangent z.
This equation is separable,
Integrate both sides and solve for 
:
Solve for 
using the initial value.
Then the particular solution is
Answer:
30.2
Step-by-step explanation:
cos(58) = 16/BC
BC = 16/cos(58) = 30.2
Answer:
6
Step-by-step explanation:
f is turned into a zero and f =x so you replace the x with zero multiply -1/2 and x then add +6 to the result
Answer:
10mins
Step-by-step explanation:
you can draw a rtd chart for this problem
rate (m/min)| time (mins) | distance (m )
regular: (300/x) | x | 300m
fist 1/4 : (300/x) | 75: (300/x) | 75m
last 3/4: | (300/x)+15 | 225:(300/x + 15) | 225m
then, make an equation for the times:
x= (75: (300/x)) + (225: ( (300/x)+15) + 2.5 = x
// get the 2.5 mins from the stop for honey, and we know that regular speed is equal to the one with a stop
solve equation to get x=-20/3 , x=10, because speed is positive, x=10 is the most reasonable answer
