Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f brainliest ?
Answer:
12
Step-by-step explanation:
I am pretty sure this is the answer. If it is correct i can give the explanation
The answer is the H. Graph.