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alukav5142 [94]
3 years ago
5

A leaky faucet in kali's house drips water at a rate of 42 gallons per week. How many gallons does the faucet drip in three days

Mathematics
1 answer:
Ratling [72]3 years ago
5 0

Amount of water that the faucet leaks in 1 week = 42 gallons

That means Amount of water that the faucet in Kali's house leaks in                 7 days = 42 gallons So The amount of water that the faucet in Kali's house leaks in 1 day = (42/7) gallons  = 6 gallons Then The amount of water that the faucet in Kali's house leaks in 3 days = 6 * 3 gallons = 18 gallons

So it can said from the above deduction that the amount of water leaked by the faucet in Kali's house is 18 gallons.

hope this help .-.

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<u>Step-by-step explanation:</u>

The sum of first n odd positive integer is n^2. The nth odd number is 2n-1.

                          i.e. 1 + 3 + ........+ (2n-1) = n^2.  

                                1 + 3 +..........+ (2n-1) = 64

                                                                n^2 = 64

                                                                    n = 8.

The positive integers between 100 and 200 which are divisible by 14 are 112, 126, 140, 154, 168, 182, 196. It is obtained by the multiples of 14 between 100 and 200.

100 = 7 * 14 + 2

200 = 14 * 14 + 4. The answer is 14 - 7 = 7

The seven numbers are

                        14 * 8 = 112

                        14 * 9 = 126

                        14 * 10 = 140

                        14 * 11 = 154

                        14 * 12 = 168

                        14 * 13 = 182

                        14 * 14 = 196

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x = 26

Step-by-step explanation:

Given

\frac{1}{3} (x - 2) = \frac{1}{5} (x + 4) + 2

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2x = 52 ( divide both sides by 2 )

x = 26

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