1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sasho [114]
3 years ago
12

Maggs invests $10,250 at a rate of 9%, compounded weekly. To the nearest whole dollar, find the value of the investment after 7

years.
Mathematics
2 answers:
Setler79 [48]3 years ago
6 0
Number of weeks in a year: 52
Weeks in 7 years: 52 x 7 = 364 

Final amount = Initial amount x (1 + interest)^(time period)

Final amount = 10,250 x (1.09)³⁶⁴
Final amount = $4.3 x 10¹⁷
LiRa [457]3 years ago
3 0
In a year:  52 weeks. 
In 7 years:  52 * 7 = 364 weeks.
10,250 * ( 1 + 0.09/52 )^364 = 
= 10,250 * ( 1 + 0.00173 )^364 =
= 10,250 * 1.00173^364 = 
= 10,250 *  1.876 = 
= $19,229.65 ≈ $19,230
You might be interested in
Ralph has a spool with 9.8 meters of wire. How many 0.14 meter pieces of wire can he cut from the spool?
Alina [70]
9.8 meters divided by .14 meter pieces. 70 pieces that Ralph can cut from the spool.
4 0
3 years ago
Given the following system of equations:
kompoz [17]

Answer:

(D) Divide the first equation, -4x + 8y = 16 , by 2.

Step-by-step explanation:

Given:

-4x + 8y = 16 \ \ \ \ equation \ 1

2x + 4y = 8 \ \ \ \ equation \ 2

We need to find the operation performed on equation so as to get resultant equation as:

-2x + 4y = 8

2x + 4y = 8

From Above we can see that there is no change in equation 2 with respect to resultant equation.

Also Resultant equation is simplified form of equation 1.

Simplifying equation 1 we get;

-4x + 8y = 16

We can see that 2 is the common multiple on both side.

Hence we will divide equation 1 with 2 we get

\frac{-4x}{2}+\frac{8y}{2}=\frac{16}{2}\\\\-2x+4y=8

which is the resultant equation.

Hence (D) Divide the first equation, -4x + 8y = 16 , by 2 is the correct option.

3 0
3 years ago
Camille is attending a fundraiser. She pays for her admission and buys raffle tickets for $5 each. If she buys 10 raffle tickets
Anna007 [38]
To spend a total of $135, Camille would have bought 27 tickets at $5 each.
7 0
3 years ago
Read 2 more answers
13.27 = t - 24.45
Alika [10]

Answer:

=

3

7

.

7

2

Step-by-step explanation:

Add

2

4

.

4

5

24.45

24.45

to both sides of the equation

1

3

.

2

7

=

−

2

4

.

4

5

1

3

.

2

7

+

2

4

.

4

5

=

−

2

4

.

4

5

+

2

4

.

4

5

4 0
2 years ago
The areas of two similar octagons are 9 m² and 25 m². What is the scale factor of their side lengths? PLZ HELP PLZ PLZ PLZ
torisob [31]

Answer:

\frac{3}{5}

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

\frac{9}{25} = (\frac{x}{y})^2 (area of similar polygons theorem)

The scale factor of their sides would be \frac{x}{y}. Which is:

\sqrt{\frac{9}{25}} = \frac{x}{y}

\frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y}

\frac{3}{5} = \frac{x}{y}

Scale factor of their sides = \frac{3}{5}

6 0
2 years ago
Other questions:
  • PLS HELPPP !<br><br>The answer is D.<br>can anyone explain why?
    15·1 answer
  • Box 2:
    9·2 answers
  • Indicate whether the following statement is true or false: An exponential growth function eventually exceeds a quadratic functio
    12·2 answers
  • Work out th following in standard form 3000 x 5000
    13·2 answers
  • A toy rocket is launched from a platform 42 feet above the ground at a speed of 91 feet per second. The height of the rocket in
    8·1 answer
  • Perform the operation. (10x2 – 10x – 6) + (x+6)
    6·1 answer
  • I need help pleaseeeeee nowplease
    5·1 answer
  • Please I need some answers
    14·1 answer
  • URGENT PLEASE ANSWER THESE
    6·1 answer
  • A rectangular lot whose perimeter is 300 ft is fenced along three sides. An expensive fencing along the​ lot's length cost $30 p
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!