Answer: the concentration of [CO]= 0.0532M
Explanation:
From The equation of reaction
2H2(g) + CO(g) ⇌ CH3OH(g)
Applying Kc= [CH3OH]/[H2]^2[[CO]
[CH3OH]= 0.00487
[CO]= x-0.00487
[H2]=(0.032-0.00487)^2=0.0271
Substitute into formula
Kc=[CH3OH]/[H2]^2[[CO]
35= 0.00487/(0.0271)^2(x-0.00487)
Simplify
x-0.00487=0.189
x= 0.00487+0.189=0.193moles
[CO]= n/C= 0.193/3.63= 0.0532M
Answer: 1, Isopropyl alcohol is mixed with water for use as a rubbing-alcohol antiseptic. It is also used in aftershave lotions, hand lotions, and other cosmetics. In industry it is used as an inexpensive solvent for cosmetics, drugs, shellacs, and gums, as well as for denaturing ethanol (ethyl alcohol).
Explanation:
Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>
![P_0*V_0 = P*V](https://tex.z-dn.net/?f=P_0%2AV_0%20%3D%20P%2AV)
![1*1 = P*0.473](https://tex.z-dn.net/?f=1%2A1%20%3D%20P%2A0.473)
![1 = 0.473\:P](https://tex.z-dn.net/?f=1%20%3D%200.473%5C%3AP)
![0.473\:P = 1](https://tex.z-dn.net/?f=0.473%5C%3AP%20%3D%201)
![P = \dfrac{1}{0.473}](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B0.473%7D)
![\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7BP%20%5Capprox%202.11%5C%3Aatm%7D%7D%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5Cbf%5Cgreen%7B%5Ccheckmark%7D)
<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
___________________________________
![\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}](https://tex.z-dn.net/?f=%5Cbf%5Cblue%7BI%5C%3AHope%5C%3Athis%5C%3Ahelps%2C%5C%3Agreetings%20...%5C%3ADexteright02%21%7D%5C%3A%5C%3A%5Cddot%7B%5Csmile%7D)
Your answer is Gallium.
Hope this helps (:
Answer:
![d=2.44\ g/cm^3](https://tex.z-dn.net/?f=d%3D2.44%5C%20g%2Fcm%5E3)
Explanation:
Given that,
The dimensions of the board is 5.54 cm x 10.6 cm X 199 cm.
The mass of the board is 28.6 kg.
Since, 1 kg = 1000 grams
28.6 kg = 28.6 × 1000 g = 28600 grams
Density = mass/volume
So,
![d=\dfrac{28600\ g}{(5.54\times 10.6\times 199)\ cm^3}\\\\d=2.44\ g/cm^3](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B28600%5C%20g%7D%7B%285.54%5Ctimes%2010.6%5Ctimes%20199%29%5C%20cm%5E3%7D%5C%5C%5C%5Cd%3D2.44%5C%20g%2Fcm%5E3)
So, the density of a board is
.