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seraphim [82]
3 years ago
7

Can you factor the common factor out of this problem? 28b+14b^2+35b^3+7b^5

Mathematics
1 answer:
Ann [662]3 years ago
7 0
This is the correct answer

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Please help I will give brainliest ​
eimsori [14]

Answer:

D

Step-by-step explanation:

is the correct answer.....

7 0
2 years ago
Simplify the expression 6 - 2x + 5+ 42. Hint: Your final expression shoul donly have<br> two terms.
il63 [147K]

Answer:

-2x+53

Step-by-step explanation:

42+5+6=53

leave the -2x

(the two is negative because we were previously subtracting)

3 0
2 years ago
3.a. Solve the following equations.<br>​
ozzi

Answer:

1. Solving \frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x) we get x=3

2. Solving \frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2} we get x=-1

Step-by-step explanation:

We need to solve the equations:

1. \frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x)

Expanding the brackets

\frac{2x}{3}-\frac{1}{3} -\frac{2x}{4}-\frac{1}{4} =\frac{2}{12}-\frac{x}{12} \\\frac{2x}{3}-\frac{1}{3} -\frac{x}{2}-\frac{1}{4} =\frac{1}{6}-\frac{x}{12}

Taking LCM on left side we get 12

\frac{2x*4-1*4-x*6-1*3}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{8x-4-6x-3}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{8x-6x-3-4}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{2x-7}{12}= \frac{1}{6}-\frac{x}{12}\\\frac{2x}{12}-\frac{7}{12}=  \frac{1}{6}-\frac{x}{12}

Add 7/12 on both sides

\frac{2x}{12}-\frac{7}{12}+\frac{7}{12} =  \frac{1}{6}-\frac{x}{12}+\frac{7}{12}\\\frac{x}{6}=\frac{1*2-x+7}{12}\\ \frac{x}{6}=\frac{-x+9}{12}  \\\frac{x}{6}=-\frac{x}{12} +\frac{9}{12}\\  \frac{x}{6}=-\frac{x}{12} +\frac{3}{4}

Adding x/12 on both sides and simplifying

\frac{x}{6}+\frac{x}{12} =-\frac{x}{12} +\frac{3}{4}+\frac{x}{12}\\\frac{x*2+x}{12}=\frac{3}{4}\\\frac{3x}{12}= \frac{3}{4}\\

Multiply both sides by 12/3

\frac{3x}{12}*\frac{12}{3}=\frac{3}{4}*\frac{12}{3}  \\Simplifying:\\x=3

So, solving \frac{1}{3}(2x-1)-\frac{1}{4}(2x+1)=\frac{1}{12}(2-x) we get x=3

2. \frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2}

Taking LCM and solving:

\frac{x-2+2x-1}{4}=\frac{2x-1}{2}\\\frac{x+2x-1-2}{4}=\frac{2x-1}{2}\\\frac{3x-3}{4}=\frac{2x-1}{2}\\

Cross multiplying

2(3x-3)=4(2x-1)\\6x-6=8x-4\\Combining\ like\ terms \ :\\6x-8x=-4+6\\-2x=2\\x=-1

So, solving \frac{x-2}{4}+\frac{2x-1}{4}=x-\frac{1}{2} we get x=-1

4 0
3 years ago
a student writes "the difference between 15 and the product of 5 and y" to describe the expression 5y-15.Explain the error.
ser-zykov [4K]
The word 'difference' indicates the use of subtraction in a Mathematical sum

The error is that the sum could be 15 - 5y instead of 5y - 15

A subtraction sum does not have the commutative properties, meaning that we cannot do the sum in any order. 

A sum 15 - 5y will give a different result with the sum 5y - 15 for the same value of y.
7 0
3 years ago
Jeff drew a circle inside a square, as shown below.
umka21 [38]

Answer:

3.14

Step-by-step explanation:

8 0
3 years ago
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