All categories

4 years ago

(14x-3)+(9x+5)????????

Mathematics

2 answers:

makkiz [27]4 years ago

3 0

Answer:

The solution to your equation is: 23x+2

nikklg [1K]4 years ago

3 0

Answer:

23x+2

Step-by-step explanation:

use distribution to find the answer

1.) move the like term to one side (combine like terms)

(14x+ 9x) + (-3 + 5)

2.) simplify

(14x+9x) + (5-3)

3.) solve each equation inside the parenthesis

14x+ 9x= 23x

5- 3 = 2

4.) now turn the answers into an equation since they are not like terms

23x+ 2

And done! Hope this helps :)

You might be interested in

An electric can opener is worth 36 dollars when it is new. After each year, it is worth half what it was the previous year. What

Likurg_2 [28]

So the equation is f(x)=36*(.5)^8, since your principal worth is 36 and it depreciates by 1/2 each year, which is 14 cents.

4 0

3 years ago

Alicia and Bennie have decided to play a game. They each draw as many flowers on paper as they can within one minute, repeating

ziro4ka [17]

Answer:

Because The Flowers Bennie drew are independent

3 0

2 years ago

Read 2 more answers

Please help, i will mark brainliest

larisa86 [58]

Answer:

1. 1,000

2. 395

Step-by-step explanation:

Hope it helps lol

3 0

2 years ago

Write a decimal that is equivalent to three and ten hundredths.

Sindrei [870]

3.1

First, we need to convert 10/100s into a decimal. We can simplify it to 1/10, which is also 0.1.

Then, we add 0.1 to 3 and get our answer: 3.1.

Hope this helped!

4 0

3 years ago

Read 2 more answers

The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba

zlopas [31]

Answer:

The probability that there are 8 occurrences in ten minutes is

option B. 0 .0771

Step-by-step explanation:

Given:

Random Variable = x

Mean number of occurrences in ten minutes is 5.3.

The probability of an occurrence is the same in any two time periods of an equal length

To Find:

The probability that there are 8 occurrences in ten minutes = ?

Solution:

Let X be the number of occurrences of the event X

$X \sim {Pois} (\lambda)$

$\lambda = E(X) = 5.3$

Possion of distribution is given by ,

$P(X=x) = \frac{e^{- \lambda} \lambda^{x}}{x!}$

Substituting the values,

$P(X=8) = \frac{e^{- 5.3} 5.3^{8}}{8!}$

$P(X=8) = \frac{(0.004994) ( 622596.904)}{40320}$

$P(X=8) = \frac{(3109.24894)}{40320}$

P(X=8) = 0.0771

3 0

3 years ago