Which inequality has infinitely many negative integer solutions
1 answer:
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Answer:
Option E) is correct
If n is an odd number then 2(n+1) represents an even number.
Step-by-step explanation:
Let X=set of all odd numbers
that is
Let Y=set of all even numbers
that is
Verify that 2(n+1) represents an even number where n is an odd number:
Put n=1 in 2(n+1) we get
2(1+1)=2(2)=4
Put n=3 in 2(n+1) we get
2(3+1)=2(4)=8
Put n=5 in 2(n+1) we get
2(5+1)=2(6)=12
and so on.
From above results we get 2(n+1) represents an even number and is belongs to the set Y when n is an odd number.
Therefore Option E) is correct
If n is an odd number then 2(n+1) represents an even number.
Answer:
7.3
Step-by-step explanation:
For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.
Distance =
X2 is 7 (X coordinate of school)
X1 is 5 (X coordinate of friend's house)
7 - 5 = 2
2^2 = 4
Y2 is 7 (Y coordinate of school)
Y1 is 0 (Y coordinate of friend's house)
7 - 0 = 7
7^2 = 49
4 + 49 = 53
= 7.2801...
<em>Round to the nearest tenth...</em>
<em>7.3</em>