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2 years ago

Which inequality has infinitely many negative integer solutions

1 answer:

5 0

A. x>-5, that is greater than -5, so not this one
B. 5<x, that means x is bigger than 5, so not
C. x is greater than or equal to -10, so not this one
D. x is less than 10, so this one

D is answer

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What is the best next step in the construction of the perpendicular bisector of

Musya8 [376]

C, not sure but C. It makes sense to me & I got it right when I did it

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3 years ago

Read 2 more answers

Write the series using summation notation. Then find the sum of the series.

ivolga24 [154]

Hello, please consider the following.

$\displaystyle 1+2+3+...+12=\sum_{k=1}^{k=12} {k}=\dfrac{12*13}{2}=6*13=78$

For the second we will need to put on the same denominator.

$\displaystyle \dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{14}=\sum_{k=1}^{k=7} {\dfrac{1}{2k}}\\\\=\dfrac{1}{2}\dfrac{420+210+140+105+84+70+60}{5*7*3*2*2}\\\\=\dfrac{1}{2}\dfrac{1089}{420}\\\\=\dfrac{1089}{840}=1.296429...$

Thank you.

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2 years ago

Find the component form of the vector that translates P(4,5) to p'.

olga_2 [115]

Answer:

The component form of the vector P'P is $\left \langle -7, 2 \right \rangle$

Step-by-step explanation:

The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;

The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7

The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2

The component form of the vector P'P = $\left \langle -7, 2 \right \rangle$

6 0

2 years ago

Will mark brainliest!!

tatiyna

The answer: 839
Correct

6 0

2 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$

And replacing we got:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

5 0

2 years ago