The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
36
Step-by-step explanation:
8x-20=5x+1
-5 -5
3x=-20+1
+20 +20
3x=21
3 3
x=7
8(7)-20
FED=36
Answer:
2*2*3*3*5
Step-by-step explanation:
180 = 18*10
18 and 10 are both composite
= 6*3 * 5*2
3,5,2 are prime but 6 is composite
= 3*2 * 3 * 5 * 2
All the factors are prime
Listing in order
2*2*3*3*5
Answer:
f(x)= 6x+9....
Step-by-step explanation:
The given equation is:
y-6x-9=0
Add 6x+9 at both sides:
y-6x-9+6x+9=0+6x+9
Solve the like terms:
on the L.H.S -6x will be cancelled out by +6x and -9 will be cancelled out by +9
y=6x+9
Now convert it in function notation:
f(x)=y
f(x)= 6x+9....
Largeur = x
longueur = 4 x
2 ( x + 4 x) = 20
2 x + 8 x = 20
10 x =20
x = 2
largeur = 2 et longueur = 8
