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sammy [17]
3 years ago
12

How do I do problem number one

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0
So you have to find something that multiples to six but also somehow either subtracts or adds to five. So I would pick 2 and 3 because two plus three is five. Then you would write out your equation
X2+2x+5x+6
This may not be the way your teacher taught however it is much easier for me to do it this way.
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Let each Square represent 1/3 unit by 1/3 unit.
Varvara68 [4.7K]
(5/3)*(7/3) = 35*(1/3)²

The area is 35 square units.
7 0
3 years ago
What is the domain and range of f(x)=2x-5
Mrrafil [7]

f(x) is a linear function with no restrictions

Domain: x = All real numbers

Range: y = All real numbers

8 0
3 years ago
Log based question, i just need help with parts b and c
Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

   The equation of the asymptote is x = 3

Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

b) ∵ f(x) = log_{2} (x-3)+1

∵ The parent function is log_{2} x

∴ x is changed to (x - 3), that means there is a translation 3 units

  to the right

∵ We add the parent function by 1, that means there is a translation

  1 unit up

* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

    make the function undefined

∵ log_{2}(0) is undefined

∴ x - 3 can not be 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∴ The domain of the function is all real number greater than 3

* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

  and the equation of the asymptote

4 0
3 years ago
Examine the pattern in the powers of i you wrote in the table, and create a rule for finding the value of large powers of i. Jus
denpristay [2]
Let N be any integer. Then

i^N=\begin{cases}1&\text{if }N\equiv0\mod4\\i&\text{if }N\equiv1\mod4\\-1&\text{if }N\equiv2\mod4\\-i&\text{if }N\equiv3\mod4\end{cases}

In other words:

(1) If N is a multiple of 4, then i^N=1.

(2) If dividing N by 4 leaves a remainder of 1, then i^N=i, since i^N=i^{4n+1} for some integer n, and from (1) we know that i^{4n+1}=i^{4n}i=i (because, obviously, 4n is a multiple of 4).

(3) If instead you get a remainder of 2, then i^N=-1. This follows from (1) as well. i^N=i^{4n+2}=i^{4n}i^2=(1)(-1)=-1.

(4) Finally, if you get a remainder of 3, then i^N=i^{4n+3}=i^{4n}i^2i=(1)(-1)(i)=-i.
5 0
3 years ago
In one year, Michael earned $6300 as a work study in college. He invested part of the money at 9% and the rest at 7%. If he rece
Nitella [24]
Let x represent invested money at 9% and y at 7%
Now we write system:
x+y = 6300
1.09*x + 1.07* y = 6300 + 493 = 6793

1.09x + 1.09y = 6867
Here we multiplied first equation with 1.09 and now we will subtract second from first:

0.02y = 74
y = 3700
x = 6300-3700 = 2600

Michael invested 2600 at 9% and 3700 at 7%
3 0
3 years ago
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