I need help... lol it feels wierd to ask
2 answers:
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Greetings!
To find the y-intercept, we can arrange the equation in slope y-intercept form:
Rearrange:
The y-intercept is: -13
To find the x-intercept, we can input the value <<0>> in the place of y, as every x-intercept only occurs when y=0:
Solve for x:
The x-intercept is:
I hope this helped!
-Benjamin
To find the y-intercept, we can arrange the equation in slope y-intercept form:
Rearrange:
The y-intercept is: -13
To find the x-intercept, we can input the value <<0>> in the place of y, as every x-intercept only occurs when y=0:
Solve for x:
The x-intercept is:
I hope this helped!
-Benjamin
Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive
coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.