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beks73 [17]
3 years ago
6

Which equation can be used to solve for b? B 5 cm 10 cm 30°

Mathematics
1 answer:
kati45 [8]3 years ago
6 0

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

Substituting the values we get

\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

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Answer:

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Step-by-step explanation:

In any "solve for ..." problem, it is useful to start by identifying where the target is and what has been done to it. Here, y is in one term on the left side of the equation and it has had these things done to it:

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So, first we add the opposite of -5x to both sides of the equation.

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2v2 -5v +3 = 0 how did I do this?
anzhelika [568]
2v2 -5v +3 = 0 \\ \\\Delta = b^{2}-4ac = (-5)^{2}-4*2*3= 25-24=1\\ \\v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{5- \sqrt{1 }}{2*2}=\frac{5- 1}{4}= \frac{4}{4}=1\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{5+ \sqrt{1 }}{2*2}=\frac{5+1}{4}= \frac{6}{4}=\frac{3}{2}=1\frac{1}{2}


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