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beks73 [17]
3 years ago
6

Which equation can be used to solve for b? B 5 cm 10 cm 30°

Mathematics
1 answer:
kati45 [8]3 years ago
6 0

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

Substituting the values we get

\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

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Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

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(x - h)² + (y - k)² = r²

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Given

x² + y² + 2x + 6y - 6 = 0

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add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

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with centre = (- 1, - 3) and r = \sqrt{16} = 4

4 0
3 years ago
Of 1. The book is on the​
artcher [175]

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Step-by-step explanation: hope it helps

5 0
2 years ago
The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i
pychu [463]
Set the function to equal zero:

-x^2 - 5x + 50 = 0

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

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Plug the values into the equation:

a = -1, b = -5, c = 50

x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}

x=\frac{5\pm\sqrt{25+200}}{-2}

x=\frac{5\pm15}{-2}

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\frac{5 + 15}{-2} = \frac{20}{-2} = -10

\frac{5 - 15}{-2} = \frac{-10}{-2} = 5

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4 0
3 years ago
James has mapped his seat and his teacher's seat on the coordinate plane at (0,10) and (–4,6). Find the distance between their s
pshichka [43]

Answer:

4√2 units (Answer C).

Step-by-step explanation:

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d = √(change in x)^2 + (change in y)^2 ).

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8 0
3 years ago
Read 2 more answers
Can someone answer these please !!!!!!
katen-ka-za [31]
A. m^2 - 36 = 0
m^2 = 36
m = √36 = 6 or -6

b. 3x^2 + 15 = 0
3x^2 = -15
x^2 = -5
x = √(-5) not possible unless complex numbers is applied
-1 = i^2
x = √(-5) = √(5i^2) = √5i

c. 4d^2 + 16 = 16
4d^2 = 0
d^2 = 0
d = 0


Hope it helped!
4 0
2 years ago
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