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beks73 [17]
3 years ago
6

Which equation can be used to solve for b? B 5 cm 10 cm 30°

Mathematics
1 answer:
kati45 [8]3 years ago
6 0

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

Substituting the values we get

\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}

Therefore the equation to solve for b is

\tan 30 = \dfrac{5}{b}

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VLD [36.1K]
A)
D+Y=50
D=Y+10

b)
Y+10+Y=50
2Y+10=50
2Y=40
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Therefore there are 20 in yearbook and 30 in drama.

To check our work:
D=Y+10
30=20+10
30=30 [CHECKS TRUE]
4 0
3 years ago
Brainliest for anyone if they get this CORRECT.
oee [108]

answer is D7/2

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4 0
3 years ago
PLEASE HURRY!!!!
Aleksandr [31]

Answer:

The answer is 40

Step-by-step explanation:

The reason for this is because. . .

(-1,-4) , (3,6)

so you have count from -1 to 3 and u will get 4, because if you can put (-1,-4) and (3,6) on a graph. If you did that then u must count horizantolly from -1 to 3 since they are on the x-axis. In the end you will get 4 since 3 minus -1 is 4. Also if your counting horizantally then that's ur width.

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To find the length, it is very simple. Subrtract 6 from -4 and you will get 10. And since the y-axis is being counted vertically, that is your length.

length = 10

To find the area, u have to do width times length so in this case you have to do 4 time 10 and you will get 40.

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8 0
3 years ago
business plans are aimed MAINLY at A.Government Regulators B.employees C.marketing firms D.potential investors
Talja [164]
Salutations!

Business plans are mainly aimed at ----

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Hope I helped :D
5 0
3 years ago
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Craig wants to prove that if quadrilateral ABCD has diagnols that biscet each other then it is a parallelogram
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Solution :

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So in the given quadrilateral ABCD, let the diagonal AC and diagonal DB intersects at a point E.

Thus in the quadrilateral ABCD we see that :

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2. Angle DCE is congruent to angle BAE and angle CDE is congruent to angle ABE. (they are alternate interior angles)

3. Line DC is congruent to line AB. (opposites sides are congruent in a parallelogram )

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Thus we see that if the diagonals of a \text{quadrilateral bisects each other}, then the quadrilateral is a parallelogram.

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3 years ago
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