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AysviL [449]
3 years ago
7

The variable y varies directly with the variable x.

Mathematics
2 answers:
Tomtit [17]3 years ago
5 0

Answer:

I believe it is 21

Step-by-step explanation:

mafiozo [28]3 years ago
5 0
21 fa show no cap but not a hunter percent ya fell ya dig
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The area of a triangle is 36 4/5 units squared and the height of the triangle 9 1/5 what is the length of the triangles base
den301095 [7]

Answer:

Height = 8 units

Step-by-step explanation:

Area of a triangle = 36\frac{4}{5} square units

                             = \frac{184}{5} square units

Height of the triangle = 9\frac{1}{5} units

                                    = \frac{46}{5} units

Formula to calculate the area of a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

\frac{184}{5}= \frac{1}{2}\times (\frac{46}{5})\times (\text{Height})

\frac{184}{5}= (\frac{46}{10})\times (\text{Height})

Height = \frac{184}{5}\times \frac{10}{46}

           = \frac{368}{46}

           = 8 units

Therefore, height of the given triangle is 8 units.

6 0
2 years ago
Read 2 more answers
The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical
Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{0.8538}

Z = -2.81

Z = -2.81 has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{0.8538}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{1.08}

Z = -2.22

Z = -2.22 has a pvalue of 0.0132

1.32% probability that his average kicks is less than 36 yards

c)

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{1.08}

Z = 2.41

Z = 2.41 has a pvalue of 0.9920

1 - 0.9920 = 0.0080

0.80% probability that his average kicks is more than 41 yards

4 0
3 years ago
Find the slope of the line containing the points (5, -1) and (-8, -4).
UkoKoshka [18]
I think it might be D
7 0
2 years ago
What is the sum of 7.8 and 7.02
Neporo4naja [7]
The sum of 
7.8 and 7.02 would be 
14.82

because 
  7.8 
+7.02
------------
14.82


hope this helps :)  



4 0
3 years ago
Read 2 more answers
Factor the expression.<br> = 28x– 14
Veseljchak [2.6K]

Answer:

14(2×-1) is the factorization of this expression

5 0
2 years ago
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