Question

-3/4x + 5/6y=15 I need to find x and y intercepts please step by step instructions.

Answer 1

Simple....

you have: $- \frac{3}{4} x+ \frac{5}{6} y=15$

To solve for x:

$- \frac{3}{4} x+ \frac{5}{6} y=15$

1.) Isolate the variable "x" (Remove y)


$- \frac{3}{4} x+ \frac{5}{6} y=15$
                      $- \frac{5}{6} y$   $- \frac{5}{6} y$

Leaving you with....

$\frac{3}{4} x=-\frac{5}{6}y +15$

2.) Divide by the variable.....

$\frac{ \frac{3}{4}x }{ \frac{3}{4} } = \frac{ -\frac{5}{6}y+15 }{ \frac{3}{4} }$

Leaving you with...

x=$-\frac{10y}{9} +20$

Now, solve for y.

To solve for y:

$- \frac{3}{4} x+ \frac{5}{6} y=15$

1.)Isolate the variable "y" (Remove x)

$- \frac{3}{4} x+ \frac{5}{6} y=15$ 
$+ \frac{3}{4}$   $+ \frac{3}{4}$

Leaving you with....

$\frac{5}{6} y= \frac{3}{4} x+15$

2.)Divide by the variable.....

$\frac{ \frac{5}{6}y }{ \frac{5}{6} } = \frac{ \frac{3}{4}x+15 }{ \frac{5}{6} }$

Leaving you with....

y=$\frac{9x}{10} +18$

x-intercept: (-20,0)

y-intercept: (0,18)

Thus, your answer.