Answer:
$ 5674.076
Step-by-step explanation:
The question is on compound interest
The formulae = A= P(1+ r/n) ^nt .......where P is the principal amount, r is the rate of interest in decimal, n is number of compoundings per year and t is the total number of years.
Given; P= $4,000.00 , r=12/100=0.12, n=2 and t=3
Substituting values in the equation A= P(1+ r/n) ^nt
A= 4000 ( 1+0.12/2)^2×3
A=4000(1.06)^6
A=$ 5674.08
Answer:
€24
Step-by-step explanation:
We can use ratios to solve this.
3:4 = 18:x
Cross multiply: 3x = 18*4
Divide: x = 18*4/3
Simplify: x = 6*4 = 24
<span><span>x=<span><span>21</span><span>/8
</span></span></span><span>Decimal Form: 2.625
</span>Hope that helped!!</span>
Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
Answer: don’t know the answer but use this link I hope I can helps u
http://kevinsworkbench.com/scopecalculator/index.html
Step-by-step explanation:
