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Galina-37 [17]
4 years ago
5

What do I do on this problem please help

Mathematics
1 answer:
insens350 [35]4 years ago
7 0
(-1.0) (-4,-1) (-1,-5) hopefully this helps (x,y)

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Line AB passes through points A (-6,6) and B(12,3). If the equation of the line is written in slope-intercept form, y=mx+b, the.
Tomtit [17]

Answer:

You wrote the question wrong...

m is not -16 it is -1/6 (that is a big difference)

y=mx+b

y=-1/6x+b

3 = -1/6(12) + b

3 = -2 + b

b=5

Step-by-step explanation:

3 0
2 years ago
In the diagram, point D divides line segment AB in the ratio of 5:3. If line segment AC is vertical and line segment CD is horiz
KIM [24]

Answer:

D

Step-by-step explanation:

First, find the coordinates of pointD if A(2,-6), B(10,2) and point D divides line segment AB in the ratio of 5:3.

If point D divides the segment AB in the ratio m:n, then

D\left(\dfrac{nx_A+mx_B}{m+n},\dfrac{ny_A+my_B}{m+n}\right)

So

D\left(\dfrac{3\cdot 2+5\cdot 10}{5+3},\dfrac{3\cdot (-6)+5\cdot 2B}{5+3}\right)=D(7,-1)

Point C has the x-coordinate the same as point A and the y-coordinate the same as point D.

Thus, C(2,-1)

5 0
3 years ago
Read 2 more answers
50% of 30, hurry &lt;3<br> its saying my question is too short so ignore what im saying rn
9966 [12]

Answer:

The answer is 15

Step-by-step explanation:

50% of 30

30 × 50 ÷ 100 = 1500/100 = 15

Thus, The answer is 15

<u>-TheUnknownScientist</u><u> 72</u>

3 0
2 years ago
Read 2 more answers
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
What is the diameter of a circle with a radius of 3.5 cm
Brums [2.3K]
The diameter of a circle is twice the size of the radius of that circle. Because the radius is 3.5 centimeters, the diameter is two times that, which is 7 centimeters. Hope this helps! And PLEASE pick me as brainliest!!!! Please
4 0
3 years ago
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