All categories

3 years ago

What is the center of (13,-2),(-1,-2),(6,-9)

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

6 0

Answer:

The center is [-1,-2

Step-by-step explanation:

Korvikt [17]3 years ago

6 0

Answer:

A(13, -2), B(-1,-2),C (6,-9)

If G is the centre so G(x,y) with x= (13-1+6)/3, y= (-2-2-9)/3

x= 6, y= -13/3= -4.3

G (-6, -4.3 )

Step-by-step explanation:

You might be interested in

Jodie ran at an average speed of 10 km/h for 15 minutes.<br> How far did she run in km?

laiz [17]

Answer:

2.5 km

Step-by-step explanation:

15 minutes is

15 minutes * 1 hour/ 60 minutes = 1/4 hour

15 minutes = 1/4 of an hour

10 km/ hour * 1/4 hour = 10/4 km = 2.5 km

5 0

2 years ago

Read 2 more answers

Which triangles are similar Please helpppp quickkkkk

kakasveta [241]

Answer:

Triangle A and Triangle B

5 0

3 years ago

A fish tank is 9 feet long how many inches is this?

Gnoma [55]

1feet = 12 incches so 12times by 9=108 inches

4 0

3 years ago

Solve for y , what is 9x+3y=4 ??

lora16 [44]

To solve for y, isolate the variable to one side.
9x+3y=4
-9x -9x
~~~~~~~~
3y= -9x+4
~~~~~~~~
3y= -9x+4 (Divide both sides by 3)

y=-3x+4

4 0

3 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago